Answer:
Correct answer: B
Step-by-step explanation:
Syntax: in piecewise functions such as the one attached, the "if:" section shows the domain, or x-axis values which that function pertains to.
In the graph, you can see that the graph is defined for 
(not-including 1 because there is an open hole there, indicating it is not part of the domain), and 
.
Now that we know the domain, we can attach it to the graphs that lie on those domains.
We see that the leftmost line appears to have a positive slope and a negative y-intercept, and that the second line should have a positive y-intercept and a negative slope.
At this point, you can just start crossing off answers that don't meet this criteria.
Cheers!!
Answer:
0.77
Step-by-step explanation:
17/22=0.772727273
Rounded to the nearest hundredth that would be
0.77
Answer:
Graph A fails the vertical line test
Step-by-step explanation:
The vertical line test will fail when a vertical line touches two or more points on the graph
Graph A will fail the vertical line test. The y axis touches two points on the graph.
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
-3
Step-by-step explanation:
