The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
A = r/2L
A(2L) = r/2L(2L) (multiply 2L to both sides to isolate r)
A(2L) = r is your answer
hope this helps
Answer: C.
Step-by-step explanation: To find the volume of something, you multiply the length, width, and height together. Since they have already multiplied the length and width together to form the base, multiply 7 by 12 (base times height) to get 84 cubic inches.
for pts (-5,12) and (-1,4)
gradient, m = (12 - 4)/(-5 - (-1)) = 8/-4 = -2
eqn of line, y = mx + c ...eqn 1
subst for m=-2 and 1 pt in eqn 1
12 = (-2) (-5)+c
c = 2
eqn of line...y = -2x + 2
