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3 years ago

If b/a=2/5, what is the value of 2 (a/b)

1 answer:

3 0

$\dfrac{b}{a}=\dfrac{2}{5}\to\dfrac{a}{b}=\dfrac{5}{2}\ \ \ |\cdot2\\\\2\left(\dfrac{a}{b}\right)=2\cdot\dfrac{5}{2}\\\\2\left(\dfrac{a}{b}\right)=5$

Answer: 2(a/b) = 5

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Because of stormy weather a pilot flying at 35,000 ft descends 8,000 ft.

babymother [125]

Answer:

35,000 - 8000=27,000 altitude

6 0

2 years ago

Each painting class Olivia teaches is h hours long. She teaches 6 classes per week. Write an expression that shows the total num

raketka [301]

Answer:

Step-by-step explanation:

If Olivia teaches 6 classes that are 1 hour, she teaches 6×1 is 6 hours.

If the classes are two hours, she teaches 6×2 is 12 hours.

Try with numbers to see what math operation you are doing. Its times.

6×h is written 6h

5 0

2 years ago

Using a formula estimate the body surface area of a person whose height is 150 cm and who weighs 80 kg.

ladessa [460]

Answer:

B. $1.83\text{ m}^2$

Step-by-step explanation:

We are asked to find the body surface area of a person whose height is 150 cm and who weighs 80 kg.

$\text{Body surface area}( m^2)=\sqrt{\frac{\text{Height (cm)}\times \text{Weight (kg)}}{3600}}$

Substitute the values:

$\text{Body surface area}( m^2)=\sqrt{\frac{150\text{ cm}\times 80\text{(kg)}}{3600}}$

$\text{Body surface area}( m^2)=\sqrt{\frac{12,000}{3600}}$

$\text{Body surface area}( m^2)=\sqrt{3.3333333}$

$\text{Body surface area}( m^2)=1.825741$

$\text{Body surface area}( m^2)=1.83$

Therefore, the body surface area of the person would be 1.83 square meters.

7 0

3 years ago

Can any kind soul help me ASAP!

CaHeK987 [17]

Answer:

Hope it helps u

Step-by-step explanation:

As we know that ,

Mean = sum of the terms/ numbers of terms

But here grouped data is given so , we use the formula

Mean=∑[f. m]/ ∑f

where f is frequency and m is mid point of each height ,

Now first we have to find the mid point of each interval, where

midpoint of each interval = (lower boundary + upper boundary)/2

m1=(150+154)/2 = 152

m2=(155+159)/2= 157,now found other by same formula, for each interval

m3= 162

m4= 167

m5=172 Now we find the midpoint of each interval ,so now

∑[f. m]=f1*m1+f2*m2+f3*m3+f4*m4+f5*m5

now putting the values of each frequency for given interval and midpoint of each interval we will get,

∑[f. m]=456+942+1296+167*x+344 = 167*x+3038

Now find,

∑f=f1+f2+f3+f4+f5

∑f=19+x

Now we have,

∑[f. m]=167*x+3038

∑f=19+x

also given mean height=161.6 cm

putt these values in above equation we get,

161.6= $\frac{167*x+3038}{19+x}$

now solve this ,

161.6(19+x)=167*x+3038

3070.4+161.6*x=167*x+3038

3070.4-3038=167*x-161.6*x

32.4=5.4*x

x=32.4/5.4

3 0

3 years ago

Please Help with angles!

777dan777 [17]

Step-by-step explanation:

003:

To solve this, we'll be using the Pythagorean theorem, $a^2+b^2=c^2$

$a^2+8^2=15^2\\a^2+64=225\\a^2=161\\a = \sqrt{161}$

004:

For the next couple questions we'll be using a fun rule called SOHCAHTOA, which stands for Sin (Opposite/Hypotenuse) Cos (Adjacent/Hypotenuse) Tan (Opposite/Adjacent). From this we can see that Tan θ is 8/ $\sqrt{161}$ .

005:

From this rule again, we can tell that sin Ф (Opposite/Hypotenuse) is going to be $\sqrt{161}$ /15.

Answer:

003: $\sqrt{161}$

004: 8/ $\sqrt{161}$

005: $\sqrt{161}$ /15

7 0

3 years ago