I'm not entirely sure what you're looking for, but here are your options. If you need a perfect square, I'd go for the 12 and 12, but I hope this helps?
The estimate of the number of students studying abroad in 2003 is 169 and the estimate of the number of students studying abroad in 2018 is 433
<h3>a. Estimate the number of students studying abroad in 2003.</h3>
The function is given as:
y = 123(1.065)^x
Where x represents years from 1998 to 2013
2003 is 5 years from 1998.
This means that
x = 5
Substitute the known values in the above equation
y = 123(1.065)^5
Evaluate the exponent
y = 123 * 1.37008666342
Evaluate the product
y = 168.520659601
Approximate
y = 169
Hence, the estimate of the number of students studying abroad in 2003 is 169
<h3>b. Assuming this equation continues to be valid in the future, use this equation to predict the number of students studying abroad in 2018.</h3>
2018 is 20 years from 1998.
This means that
x = 20
Substitute the known values in the above equation
y = 123(1.065)^20
Evaluate the exponent
y = 123 * 3.52364506352
Evaluate the product
y = 433.408342813
Approximate
y = 433
Hence, the estimate of the number of students studying abroad in 2018 is 433
Read more about exponential functions at:
brainly.com/question/11464095
#SPJ1
3/4 w = 9
multiply by 4/3 on both sides
4/3 x 3/4 w = 9 x 4/3
w = 9 x 4/3
Simplify that
w = 3 x 4
w = 12
So your final answer is
Answer:
g(1) = -65; g(n) = g(n-1) -15
Step-by-step explanation:
Using n = 1, 2, 3, we can find the first three terms of the sequence:
g(1) = -50 -15 = -65
g(2) = -50 -15(2) = -80
g(3) = -50 -15(3) = -95
The first term of the arithmetic sequence is -65, so that is g(1). Each next term is 15 less than the one before, so the recursive formula is ...
g(n) = g(n-1) -15
The complete recursive function definition requires both parts:
g(1) = -65
g(n) = g(n-1) -15
Answer:
the correct answer is C....I hope
