Two numbers that gives twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90 are -10 and 4
Given :
Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90.
Let a and b be the two unknown numbers
Lets frame equation using the given statements
Twice the sum of a number and 3 times a second number is 4.
the difference of ten times the second number and five times the first is 90
Now use these two equations to solve a and b
Add both the equations
Now find out 'a'
The two numbers are -10 and 4
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Answer:
Ans. 64 cm
Step-by-step explanation:
we have to use the ratio of actual distance and distance on projection here.
Given,
Ratio of distance in projection and actual distance is 1:200,000
That means, 1 cm in projection will be 200,000 cm in actual distance.
Here,
Actual distance is 128 km.
we know, 1 km=100,000 cm
Now, 128 km=128,00,000 cm
So, actual distance is 128 00 000 cm.
Since, 200000 cm in actual distance means 1 cm in projection.
So,
for 12800000 cm in actual distance means 12800000/200000 cm in projection.
So, in the screen distance will be-
12800000 / 200000
=64 cm
Answer:
143º
Step-by-step explanation:
You want to find m<HBD
which is m<HBA minus m<BAD
180º minus 37º equals 143º
m<HBD is equal to 143º
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Can anyone who sees this answer my latest question?
I need help with it very soon.
Answer:
c. 25/100
Step-by-step explanation:
The given fraction is 1/4.
Here we need to find the equivalent to 1/4.
It c. 25/100
Let me explain.
Multiply 1/4 by 25 both the numerator and the denominator.
1/4 *25/25 = 1*25 / 4*25
= 25/100
All other fractions are not equivalent to 1/4
Answer: c. 25/100
Thank you.
Answer:
Step-by-step explanation:
Giving out answers for a free test is something wrong but something I can help is to go review or I can help you review because algebra 1 is one easy of a topic when you really hook yourself to it.
