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docker41 [41]
3 years ago
10

Please help not sure if baby has any correct ​

Mathematics
1 answer:
Elodia [21]3 years ago
5 0
So I think maybe the example for the first problem created some confusion, and you may want to have your child take another look.

If we numbered the top half 1 to 9 going from left to right, numbers 1, 2, 6, 7 and 8 are right. They worked because the top number (numerator) perfectly fit into the bottom number (denominator). This is not true for the rest.

The key is to find the largest number that you can think of that will go into BOTH the top and the bottom evenly.

So for number 3: 18/24; 18 does not fit evenly into 24. The highest number that will fit into both is 6, so you divide both top and bottom by 6 and your answer is 3/4.

Number 4: 45/54; the highest number that goes into both is 9, so you divide both top and bottom by 9 and your answer is 5/6.

Number 5: 55/66; the highest number that can go into both is 11, so the answer is 5/6.

Is this making sense?

The bottom, numbering 1 to 9 from left to right. The correct ones are 1, 6 and 9.

For 2: 14/41 is about 15/40. Both can be divided by 5, so the answer is 3/8.

For 3: 20/81 is about 20/80, and 2/8 is close, but can still be divided by 2, so the answer is 1/4.

For 4: 24/49 is closer to 25/50 than 20/50. 25/50 can be divided by 25, so the answer is 1/2.

For 5: it was all correct, but the answer can be further reduced from 2/8 to 1/4.

For 7: 23/72 is about 25/75, and 25 goes into both, so it reduces to 1/3.

For 8: 13/21 is about 15/20, and 5 goes into both, so the answer is 3/4.

As your child continues to learn this, remember that if he or she gets an answer like 2/6 or 6/12, they should ask themselves if they can further reduce the fractions- 2/6 reduces to 1/3, and 6/12reduces to 1/2. I know it's confusing, but they do get the hang of it with practice
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The length of a flea is approximately one million times longer than the width of DNA. Which is a reasonable measure for the widt
scZoUnD [109]

Answer:

The answer is A

Step-by-step explanation:

That is because one million has 6 digits and I'm guessing that the flea is measured in millimeters. So you just add the two decimal places. So, you add the one million (count the number of zeroes in a million) to the number of decimal places that the dot was moved. So from a measure of meter you move the dot one place right and you decrease the measuring unit. So, first is meter then centimeter and then millimeter.

5 0
3 years ago
I need the answer to this please help
Brums [2.3K]

Answer:

-1/11

Step-by-step explanation:

\frac{11x}{12} -\frac{1}{6} =\frac{-1}{4}    add 1/6 to both sides

\frac{11x}{12} =\frac{1}{6} -\frac{1}{4}  make the same denominator 12 on the right side

\frac{11x}{12} =\frac{1}{6}*\frac{2}{2}  -\frac{1}{4}*\frac{3}{3}  solve

\frac{11x}{12} =\frac{2}{12} -\frac{3}{12} =\frac{2-3}{12} = \frac{-1}{12}

\frac{11x}{12}*12 =\frac{-1}{12} *12 multiply by 12 both sides

11x= -1 divide by 11

x= -1/11

7 0
3 years ago
Jose added up his work hours for his paycheck. Last week he worked hours 25 5/8. This week he worked hours 32 5/6. How many tota
babymother [125]

Answer:

58 hours

Step-by-step explanation:

First week: 25 5/8 hours = 25 hrs 37 mins and 30 sec

Second weeK: 32 5/6 hrs = 32 hrs and 50 mins

To find the toal time in minutes

(37 + 50) mins = 1 hr 27 mins

Threfore, total number of hours he worked in two weeks:

(25 + 32 + 1) hrs = 58 hours

8 0
4 years ago
The circumference of a circle is 50 inches. What is the radius?
GalinKa [24]

Answer:

The answer is 7.96 inches.

Step-by-step explanation:

radius= Circumference/ 2 Pi  = 50/2 3.14 = 7.96

7 0
3 years ago
How to do these two pls help !!!
Blababa [14]

a. i. Calculate the area of the complete semicircunference, and substract the area of both internal semicircunference.

Let A the area that we need to calculate, let B the area of the total semicircunference, and C the sum of the internal semicircunferences.

A = B - C \\A = \pi (28)^2 - 2\pi (14)^2 \\A = \pi((28)^2 -2 (14)^2) \\A = 392\pi \ cm^2

a. ii. The same idea. Let P the perimeter that we need to calculate, and let P' the perimeter of the total semicircunference, and Q the sum of the perimeters of the internal semicircunferences.

P = P' - Q\\P = 2\pi (28) - 4\pi (14)\\P = 56\pi - 56\pi = 0


b. i A = 14^2 - 4(\pi (7)^2)/4\\A = 196 - 49\pi\ cm^2

b. ii P = 4(14) - 2\pi(7) = 56- 14\pi\ cm

7 0
3 years ago
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