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3 years ago

Kennedy was asked to solve the equation

Mathematics

2 answers:

avanturin [10]3 years ago

6 0

Answer:

C No; -4 -8 is -12 and 3 x -12 is -36.

Step-by-step explanation:

Let's solve your equation step-by-step.

d /3 + 8= −4

Step 1: Simplify both sides of the equation.

1 /3 d + 8 = −4

Step 2: Subtract 8 from both sides.

1 /3 d + 8 − 8 = −4 − 8

1 /3 d = −12

Step 3: Multiply both sides by 3.

3*( 1 /3 d) = (3)*(−12)

d=−36

Hope this helps! :}

olganol [36]3 years ago

4 0

Answer: C
First you have to get rid of the 8 because it is a constant. -4-8=-12. Then, you multiply out the denominator to isolate the variable. This means -12*3=-36

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Which expressions are equivalent??

Brilliant_brown [7]

Given:

The given expression is $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$

We need to determine the equivalent expression.

Option A: -1

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is not equivalent to -1.

Hence, Option A is not the correct answer.

Option B: 29

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to 29.

Hence, Option B is the correct answer.

Option C: $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Let us rewrite the given expression.

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, Option C is the correct answer.

Option D: $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Rewriting the expression, we get;

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent not to $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Thus, Option D is not the correct answer.

Option E: $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Multiplying the terms within the bracket, we get;

$2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Thus, Option E is the correct answer.

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The coordinates of the 3 of the vértices of a parallelogram are (-7, 3), (-6, 1), and (-4, 5). What is the equation for the line

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Slope of line one :

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So, equation of other line passing through (-4,5) and have slope of -0.5 is :

y-5 = -0.5( x-(-4))

y-5 = -0.5x - 2

y + 1/2x = 3

2y + x = 6

Therefore, equation of line containing the (-4, 5) is 2y + x = 6.

Hence, this is the required solution.

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