Ask question

Ask question

All categories

2 years ago

9

The selling price for a classic car is $16000 which is. $1000 more than three times its original price. What was the original pr

ice of the car?

1 answer:

babunello [35]2 years ago

6 0

1) Subtract 1,000 from 16,000.
Now you have 15,000.
2) Divide 15,000 by 3.
The original price of the car was $5,000.

You might be interested in

On a map, 2.5 inches represents 52 miles. What is the actual distance represented by 5 inches on the map?

nikklg [1K]

Answer:

104 miles

Step-by-step explanation:

52/2.5 = 20.8

20.8 miles = 1 inch

20.8 x 5

104 miles = 5 inches

7 0

2 years ago

Read 2 more answers

How are operations with variables like operations with real numbers?

amid [387]

Answer:

The relation between inputs and outputs is given by an equation called the equation of function. Since the outputs are also real values, hence, reasoning by analogy, you may use the arithmetical operation between functions (addition, subtraction, multiplication, division) to produce new functions.

6 0

2 years ago

What do I have to put

saw5 [17]

Answer: for question 1, i think you have to put yes because absolute value is always positive so it´s 6.5 and the opposite of -6.5 is 6.5

Step-by-step explanation:

7 0

2 years ago

In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.

Sveta_85 [38]

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

$\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm$

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

$\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M$

In the right triangle, two acute angles are always complementary, so

$m\angle M=90^{\circ}-m\angle P=90^{\circ}-21^{\circ}=69^{\circ}$

Thus,

$MH=1.43\cos 69^{\circ}\approx 0.51\ cm$

7 0

2 years ago

Represent A Quadratic Function Using:

Pani-rosa [81]

Sub the Xs in the eqn

5 0

1 year ago