Find the equation, in vertex form, for a parabola with a vertex of (2,-5) that goes through the point (3,4).

1 answer:

7 0

Y=9(x−2)²−5 is the solution

Explanation in full below

Using the vertex co-ordinates we can deduct the formula
y=a(x-2)²-5

using the co-ordinate (3,4), use x=3, y=4 to find a

y=a(x-2)²-5
4=a(3-2)² -5
4=a(1)²-5
4=a-5
a=9

Subsituting a into the first equation
y=a(x-2)²-5
y=9(x-2)²-5

The solution is y=9(x-2)²-5

You might be interested in

Give that each figure shown below is a trapezoid. Find the missing values.

Lyrx [107]

Answer:

EF=22

C=70°

B=110°

Step-by-step explanation:

Trapezoids have to have a total of 360° and there are complementary angles.

6 0

3 years ago

What number must you add to complete the square x^-8x=39

notsponge [240]

Answer:

Given equation: $x^2-8x =39$

when we complete the square , we take half of the value of 8 , then square it, and added to the left sides, we get;

$x^2-8x+4^2 = 39 +4^2$

∵8 is the value $(\frac{8}{2})^2$

Notice that, we add this both sides so that it maintains the equality.

then;

$x^2-8x+4^2 = 39 +4^2$

$(x-4)^2 = 39 + 16$ [ $(a-b)^2 = a^2-2ab+b^2$ ]

Simplify:

$(x-4)^2 =55$

The number must be added to complete the square is, $4^2 = 16$

3 0

3 years ago

Read 2 more answers

Which pair of rectangles is similar? a b c d

cricket20 [7]

B) the one that has the sides 4 & 8 and 3 & 6.

The length on both of these rectangles are twice as long as the width

one rectangle goes from a width of 4 and its length is doubled to a length of 8
it is similar to the 3 & 6 because the width of 3 is doubled to get the length of 6

hope this helps

3 0

3 years ago

Y= 4/5 x-7 what are the y and x intercepts?

solmaris [256]

The x intercept is (8.75, 0) and y - intercept is (0, -7)

Solution:

Given that we have to find the x and y intercepts

Given equation is:

$y = \frac{4}{5}x - 7$