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maksim [4K]
3 years ago
15

In beijing in 2008 the womens 3,000 meter steeplechase became an olympic event what is the distence in kilometer

Mathematics
1 answer:
Talja [164]3 years ago
8 0
1,000 meters=1 kilometer

\frac{3000}{1000}=3

Answer: 3 km
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vekshin1

Answer:

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Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
If r=10 and s=31 find R. Round to the nearest tenth
Vsevolod [243]

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

tan\alpha=\frac{opposite}{adjacent}

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Then, you get:

R=arctan(\frac{10}{31})\\\\R=17.9\°

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3 years ago
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Simplify <br> 3 (2x+4y-2z)+7 (x+y-4z)
Dima020 [189]
6x+12y-6z+7x7y-28z= 13x+19y-34z
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Determine whether the points (–3,–2) and (3,2) are in the solution set of the system of inequalities below. y ≤ ½x + 2 y &lt; –2
lana [24]

Given:

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y

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Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.

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Since the point (3,2) does not satisfy the second inequality, therefore (3,2) is not in the solution set of the given system of inequalities.

7 0
3 years ago
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