Area of a rectangle can be calculated by multiplying the length by the height.
So:
l x w
3 x 13
39 cm squared
Area of a triangle can be calculated by multiply the length by the height and dividing by two. So:
1/2 x l x w
1/2 x 10 x 8
40 m squared
Answer:

Step-by-step explanation:

<span>Simplifying
x2 + 8x + y2 + -2y = 64
Reorder the terms:
8x + x2 + -2y + y2 = 64
Solving
8x + x2 + -2y + y2 = 64
Solving for variable 'x'.
Reorder the terms:
-64 + 8x + x2 + -2y + y2 = 64 + -64
Combine like terms: 64 + -64 = 0
-64 + 8x + x2 + -2y + y2 = 0
The solution to this equation could not be determined.</span>
Answer:
x is more than or equal to 77
Step-by-step explanation:
EDIT: Picture
33) When adding matrices, just add the numbers that are in the same spot. In this problem we are given A and C, and we are asked to find B if A + B = C
So B = C - A
![\left[\begin{array}{ccc}2&-1&-3\\1&4&-2\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-1%26-3%5C%5C1%264%26-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
-
![\left[\begin{array}{ccc}4&9&-2\\-3&5&7\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%269%26-2%5C%5C-3%265%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
=
![\left[\begin{array}{ccc}-2&-10&-1\\4&-1&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-10%26-1%5C%5C4%26-1%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
34) When multiplying matrices, the number of columns in the first matrix needs to be the same as the number of rows in the second matrix. Then the outcome will have the same number of rows as the first matrix and same number of columns as the second matrix. In this case, the result will be a 2x2.