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Arte-miy333 [17]
2 years ago
5

Evaluate sequences in recursive form g(1) = 4 { g(2) = -3 g(n)=g(n-2)•g(n-1)

Mathematics
1 answer:
dolphi86 [110]2 years ago
7 0

Answer:

when i tell you math-way works wonders

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Problem page rita drive 420 miles using 18 gallons of gas. at this rate, how many gallons of gas would she need to drive 357 mil
bulgar [2K]
The answer is 8,330 
because you have to take 420 and divied it by 18 and youll get 23.33333 then you times it to 357 

hope you are satisfied 
3 0
3 years ago
What is the unit rate of $46 for 5 toys
Nookie1986 [14]
I think it would be $9.20 because 46 divided by 5 = 9.2
8 0
2 years ago
Sam is moving bags of soil from a loading dock into a storeroom. The top soil weighs 40 pounds per bag and the mulch weighs 20 p
Levart [38]

Answer:

40x+20y\leq 480

Step-by-step explanation:

Givens

  • The top soil weighs 40 pounds per bag.
  • The mulch weighs 20 pounds per bag.
  • The cart can only carry up to 480 pounds.

Notice that the restriction is a maximum of 480 pounds, that means the inequality must include the sign \leq.

Now, let's call x the top soil and y the mulch, the inequality that represents this problem, would be

40x+20y\leq 480

3 0
3 years ago
Read 2 more answers
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
2 years ago
Enter an equation in standard form for the line.<br> Slope is -5, and (-6, -10) is on the line.
fredd [130]
Y+10=-5(x+6)
Y +10= -5x-30
5x+y+40=0
3 0
2 years ago
Read 2 more answers
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