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erastova [34]
3 years ago
8

Simplify x * x^5 / x^2 * x

Mathematics
1 answer:
elena55 [62]3 years ago
7 0
It’s x^3, i guess hope this helps
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How to do this question plz <br>question 2​
sashaice [31]

Answer:

a) x+3=19

Step-by-step explanation:

a)

x is the age of Ronald , Collin is three years older than Ronald , so if we add up x(Ronald's age) and 3(the difference between both of their ages), we would get Collin's age(19) . That is the explanation for this equation.

b)

x+3=19

x=19-3

x=16

thus , x is 16 , in other words , Ronald's age is 16.

3 0
4 years ago
1. Find the mean, median, and mode of this data set.<br> 76, 74, 78, 72, 73, 80, 49, 72, 83
aliina [53]

Mean 74
Median 73
Mode 72
3 0
3 years ago
Pleas answer quickly
alexandr1967 [171]

Step-by-step explanation:

I don't understand, why there is this segment about the 0 degrees Kelvin.

any material, water or the glass the water is in, or the air, or the floor or the wall : the higher the temperature (the scale does not matter, as long both temperatures use the same), the more energy it contains (the faster the particles in that substance are moving/vibrating).

therefore a glass of water with 80 degrees will have much more energy than one with 20 degrees.

the same way an aluminum can (the actual name of that material is aluminium, but Americans seemingly cannot pronounce that) with 30 degrees has more energy than one with 20 degrees.

3 0
3 years ago
A cylinder has a radius of 30 ft and a height of 19 ft. What is the exact surface area of the cylinder?
Ad libitum [116K]
A=2\pi r(r+h)\\&#10;A=2\pi\cdot30\cdot(30+19)\\&#10;A=60\pi\cdot49\\&#10;A=2940\pi\hbox{ ft}^2
4 0
4 years ago
Read 2 more answers
A scientist inoculates mice, one at a time, with a disease germ until he finds 2 that have contracted the disease. if the probab
AnnyKZ [126]
<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
5 0
3 years ago
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