It will be itself because 1 cannot be divided by the number itself
<span>c. JK
that is where the two planes intersect at
I hope this helps, good luck! :)</span>
Answer:
Assuming order does not matter, the probability of selecting all midsize cars is 0.000277373, or
.
Step-by-step explanation:
First, we must find the n(Total arrangements of selections)=(8+15)C6
n(Total arrangements of selections)=23C6
n(Total arrangements of selections)=100,947
Second, we must find the n(Arrangements where all are midsize cars)=8C6
n(Arrangements where all are midsize cars)=28
To find the probability of selecting all midsize cars, we divide the n(Arrangements where all are midsize cars) by the n(Total arrangements of selections):
P(All midsize cars)= ![\frac{28}{100,947}](https://tex.z-dn.net/?f=%5Cfrac%7B28%7D%7B100%2C947%7D)
P(All midsize cars)=
=0.000277373.
Answer:
I don't see an attatchment :( can u tell me the problem?
Step-by-step explanation: