All categories

3 years ago

In rectangle ABCD, if the coordinates of A are (0, 0) and of C are (r, s), find the coordinates of B and D.

2 answers:

6 0

So in your problem where there is an image that show a rectangle ABCD and its coordinates is A(0,0) and of C(r,s), the ask is to find the coordinates of B and D. The best thing you will do is analyze the diagram and you will came up with the coordinates of B(0,s) and D(r,0)

goldenfox [79]3 years ago

3 0

Answer:

Answers are (r,0) and (0,s)

Step-by-step explanation:

Given that in a rectangle ABCD, one vertex is the origin (0,0) A

The opposite vertex C is having coordinates as (r,s)

Since a rectangle has angle 90 we have x axis as one side and y axis as other side.

Length = r and width =s (since coordinates of C are (r,s))

Hence other coordinate B on x axis would be = (r,0)

and D on y axis = (0,s)

Answers are (r,0) and (0,s)

You might be interested in

Find all solutions of the equation in the interval [0, 2pi).

natali 33 [55]

Answer:

Step-by-step explanation:

Begin by squaring both sides to get rid of the radical. Doing that gives you:

$sin^2x=1-cosx$

Now use the Pythagorean identity that says

$sin^2x =1-cos^2x$ and make the replacement:

$1-cos^2x=1-cosx$ . Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:

$1-cos^2x+cosx-1=0$ and then simplify to

$cosx-cos^2x=0$

Factor out the common cos(x) to get

$cosx(1-cosx)=0$ and there you have your 2 trig equations:

cos(x) = 0 and 1 - cos(x) = 0

The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at

$x=\frac{\pi }{2},\frac{3\pi}{2}$

The second equation simplifies to

cos(x) = 1

Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.

So, in the end, your 3 solutions are

$x=\frac{\pi}{2},\pi,\frac{3\pi}{2}$

8 0

3 years ago

Give the formula for the area of the following shapes. .

mamaluj [8]

Let's go shape by shape!

The area of a rectangle can be calculated as follows:

$L * W = area$ where L = length and W = width

The area of a trapezoid can be calculated as follows:

$\frac{( b_{1} + b_{2})*H}{2} = area$
where b1 and b2 = lengths of the base and H = height of the shape

The area of a parallelogram can be calculated as follows:

$B * H = area$ where B = length of the base and H = height of the shape

3 0

3 years ago

Which equation is equivalent to the formula below? y = a(x – h)^2 + k

PolarNik [594]

Answer:

See below.

Step-by-step explanation:

The given equation is in vertex form. We can convert it to standard form as follows:

y = a(x - h)^2 + k

y = a(x^2 - 2hx + h^2) + k

y = ax^2 - 2ahx + (ah^2 + k) (answer).

8 0

3 years ago

Read 2 more answers

Plz help ill mark u brainliest

egoroff_w [7]

Answer:

Part A: 3,

Part B: - 4

Step-by-step explanation:

~ Part A ~

The problem would be in terms of such an expression: ( - 6 - ( - 3 )^2 )/ -5

Now knowing the expression, let us simplify in terms of basic algebra:

( -6 - 9 )/ -5 = ( - 15/ - 5 ) = Answer; 3

~ Part B ~

We know the problem to be p^2/ r, but we must substitute the value of p being -10, and r ⇒ -25: ( - 10 )^2/ -25

Now let us simplify the expressions:

( - 10 )^2/ -25 = 100/ - 25 = Answer; -4

5 0

3 years ago

Factor the expression completely X^2-8x+16

IgorC [24]

[ x² - 8x + 16 ] is a perfect square.

It has 2 factors. Both of them are (x - 4) .

7 0

3 years ago