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kvasek [131]
3 years ago
5

Are 3/4 and 16/20 equivalent? Why or why not is one fraction smaller/larger than the other? How do you know

Mathematics
1 answer:
Jet001 [13]3 years ago
6 0

Answer:

No they are not equivalent because 3/4 would be equivalent to 6/8, 9/12, 12/16/ 15/20. 16/20 would be the greatest fraction because in its simplest form it would be 4/5.

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2. Solve each equation. Check your solutions.<br> b. 5 +<br> - 16
Ber [7]

Answer:

Step-by-step explanation:

-11

4 0
3 years ago
Lela and Pepe are playing a video game. The ratio of Lela’s game score to Pepe's score is 2 : 5. Then Lela completes a quest and
Fed [463]

Answer:        Lela's original score was 16.

Step-by-step explanation:

Alright lets get started.

Suppose Lela score was L.

Suppose Pepe score was  P.

The ratio of Lela’s game score to Pepe's score is 2:5

So the equation will be

\frac{L}{P} = \frac{2}{5}

Cross multiplying

5\times L=2\times P

P=\frac{5\times L}{2}.................equation 1

Then Lela completes a quest and scores 12 bonus points. The new ratio becomes 7:10

\frac{L+12}{P} =\frac{7}{10}

Cross multiplying

10(L+12)=7P

Plugging value of P from equation 1

10(L+12)= 7\times\frac{5L}{2}

20L+240=35L

15L=240

L=16

Hence the score of Leela originally was 16.                Answer

5 0
3 years ago
The sum of two nonzero real numbers is 4 times their product. What is the sum of the reciprocals of the two numbers
zlopas [31]

Answer:

  4

Step-by-step explanation:

If the two numbers are 'a' and 'b', the sum of their reciprocals is ...

  \dfrac{1}{a}+\dfrac{1}{b}=\dfrac{a+b}{ab}=\dfrac{4ab}{ab}=\boxed{4}

The sum of their reciprocals is 4.

7 0
3 years ago
Please help!
nirvana33 [79]
I would say you have a probability of 1/4 to pick a 3 in the first round and 1/3 in the second round
1/4 plus 1/3 = 7/12
3 0
3 years ago
Consider the equation y = a - bx. If y = 6 when x = 1 and y = 0 when x = 2, find . = х
Trava [24]

Answer:

see explanation

Step-by-step explanation:

(a)

y = \frac{a}{x} - bx

substitute y = 6 , x = 1 into the equation

6 = a - b → (1)

substitute y = 0 , x = 2 into the equation

0 = \frac{a}{2} - 2b ( multiply through by 2 to clear the fraction )

0 = a - 4b → (2)

multiply (1) by - 4

- 24 = - 4a + 4b → (3)

add (2) and (3) term by term to eliminate b

- 24 = - 3a + 0

- 24 = - 3a ( divide both sides by - 3 )

8 = a

substitute a = 8 into (1) and solve for b

6 = 8 - b ( subtract 8 from both sides )

- 2 = - b ( multiply both sides by - 1 )

2 = b

Then a = 8 and b = 2

(b)

when x = 4

y = \frac{8}{4} - 2(2) = 2 - 4 = - 2

8 0
2 years ago
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