3 years ago

Write the equation of a line which has slope

Mathematics

1 answer:

marishachu [46]3 years ago

4 0

error_code- 67584598379432332

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A ball of radius 11 has a round hole of radius 5

inn [45]

Answer:

3,847.40376

Step-by-step explanation:

Volume of a sphere=

4/3π(11)³=5,575.27976

Volume of a cylinder=

π(5)²(22)=1,727.876

Total volume=

5,575.27976-1,727.876=3,847.40376

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4 years ago

Solve by the linear combination method (with or without multiplication).

iris [78.8K]

I hope this helps you

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3 years ago

CosA + cosB - cosC = -1 + 4cosA/2 cosB/2 sinC/2

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

(cos A+ cos B)-cos C

$=2cos \frac{A+B}{2}cos \frac{A-B}{2}-cos C~~~...(1)\\A+B+C=180\\A+B=180-C\\\frac{A+B}{2}=90-\frac{C}{2}\\cos \frac{A+B}{2}=cos(90-\frac{C}{2})=sin \frac{C}{2}\\cos C=1-2sin^2\frac{C}{2}\\(1)=2 sin \frac{C}{2} cos \frac{A-B}{2}-1+2sin^2\frac{C}2}\\=2sin\frac{C}{2}[cos \frac{A-B}{2}+sin \frac{C}{2}]-1~~~...(2)\\\\now~again~A+B+C=180\\C=180-(A+B)\\sin\frac{C}{2}=sin(90-\frac{A+B}{2})=cos \frac{A+B}{2}\\(2)=2sin\frac {C}{2}[cos \frac{A-B}{2}+cos \frac{A+B}{2}]-1\\$

$=-1+2sin\frac{C}{2}*2cos \frac{\frac{A-B}{2} +\frac{A+B}{2} }{2} cos \frac{\frac{A-B}{2} -\frac{A+B}{2} }{2} \\=-1+4sin\frac{C}{2} cos \frac{A}{2} cos\frac{-B}{2} \\=-1+4 cos \frac{A}{2} cos \frac{B}{2} sin \frac{C}{2}\\(cos(-B)=cos B)$