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Lana71 [14]
3 years ago
5

How do you compare two-way frequencies in a relative frequency table

Mathematics
1 answer:
Nikolay [14]3 years ago
3 0
  • To avoid such problems when comparing the categorical variables in a two-way frequency table, we need to exam the table by separate categories (rows or columns). When a relative frequency is determined based upon a row or column, it is called a "conditional" relative frequency.
  • Two-way relative frequency tables show what percent of data points fit in each category. ...
  • For example, here's how we would make column relative frequencies:
  • Step 1: Find the totals for each column.
  • Step 2: Divide each cell count by its column total and convert to a percentage.
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A hairstylist schedules 1/4 hour to trim a customers hair and 1/6 hour to style the customers hair. the hairstylist plans to wor
Lana71 [14]
To make it simple make them all the same fraction

6/24 to trim 4/24 to style and she wants to work for 80/24 hours for 5 days

if each appointment she wants to take 6/24 to trim and 4/24 to style then every appointment will take 10/24 of an hour.

she wants to do 80/24 so she can do 8 appointments a day if each take 10/24

8 appointments a day 5 days a week

8x5= 40 
3 0
3 years ago
Solve for x in 2/3=x/4+x/3
shusha [124]

x = 8/7

hope this helps on whatever you are doing!

8 0
3 years ago
Read 2 more answers
What is (40x33)+(4)x4??<br> Good luck
MrRa [10]

Answer:

1336

PLZ let me know if im wrong!!!

5 0
2 years ago
The formula Upper V equals LWH is used to find the volume of a box. If the length of a box is increased 4 times​, the width is i
marysya [2.9K]

Answer:

the volume of the box increases 48 times compared to the 1st one.

Step-by-step explanation:

Volume of the box (1) = LWH

  • length of a box is increased 4 time = 4L
  • width is increased 4 times​ = 4W
  • the height is tripled​ = 3H

=> The new volume of the box = 4L * 4W * 3H = 48LWH  

So the volume of the box increases 48 times compared to the 1st one.

4 0
3 years ago
9. Determine how long it takes for 80% of the material to decay.
Vilka [71]

Using an exponential function, it is found that it takes 18.6 days for 80% of the material to decay.

The amount of a substance after t days is modeled by:

A(t) = A(0)e^{-kt}

In which:

  • k is the decay rate, as a decimal.
  • A(0) is the initial amount.

The half-life is of 8 days, hence A(8) = 0.5A(0), and this is used to find k.

A(t) = A(0)e^{-kt}

0.5A(0) = A(0)e^{-8k}

e^{-8k} = 0.5

\ln{e^{-8k}} = \ln{0.5}

-8k = \ln{0.5}

k = -\frac{\ln{0.5}}{8}

k = 0.08664339757

Hence:

A(t) = A(0)e^{-0.08664339757t}

The time it takes for 80% of the material to decay it t for which A(t) = 0.2A(0), hence:

0.2A(0) = A(0)e^{-0.08664339757t}

e^{-0.08664339757t} = 0.2

\ln{e^{-0.08664339757t}} = \ln{0.2}

-0.08664339757t = \ln{0.2}

t = -\frac{\ln{0.2}}{0.08664339757}

t = 18.6

It takes 18.6 days for 80% of the material to decay.

To learn more about exponential functions, you can take a look at brainly.com/question/24906920

5 0
3 years ago
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