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Ganezh [65]
3 years ago
7

If f(x) =

class="latex-formula">, which of the following describes the graph of f(x) - 5?
A. The graph of f(x) - 5 is a vertical shift of f(x) = x^{2} five units up.

B. The graph of f(x) - 5 is a vertical shift of f(x) = x^{2} five units down.

C. The graph of f(x) - 5 is a horizontal shift of f(x) = x^{2} five units to the right.

D. The graph of f(x) - 5 is a horizontal shift of f(x) = x^{2} five units to the left.
Mathematics
1 answer:
balu736 [363]3 years ago
6 0
I'm pretty sure it'd be answer B.
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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

  • \displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx}  \int\limits^{x^2}_0 t^2+1 \text{ dt}  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

  • \displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]
  • where u represents any function other than a variable

For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

  • \displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)  

Simplify the expression by distributing 2 and 2x inside their respective parentheses.

  • [-(8x^2 +2)] + (2x^5 + 2x)
  • -8x^2 -2 + 2x^5 + 2x

Rearrange the terms to be in order from the highest degree to the lowest degree.

  • \displaystyle2x^5-8x^2+2x-2

This is the derivative of the given integral, and thus the solution to the problem.

6 0
3 years ago
1. (i) Express 2704 as a product of its prime factors.
lidiya [134]

Answer:

all answers below

Step-by-step explanation:

(i) 2704 = 2^4 x 13^2

(ii) as both indices (the powers) are divisible by 2, it is a perfect square.

(iii) as both indices are not divisible by 3, it is not a perfect square.

8 0
3 years ago
What is the definition of css
BabaBlast [244]

Cascading Style Sheets, a sheet language used to describe a made up language like HTML, how it's put on paper.

3 0
3 years ago
Read 2 more answers
What does B(0) = 0 mean
MissTica

Answer:

It means <u>what is the y-value of the given function, if 0 is substituted in for x.</u>

Hope this helps!

3 0
3 years ago
the absolute value of the sum of two different integers with the same sign is 8. Pat says there are three pairs of integers that
Irina18 [472]
Disagree
They say there are three pairs of integers that match, well..
1+7=8
2+6=8
3+5=8

-1+-7=-8
-2+-6=-8
-3+-5=-8
The same applies to negative integers because the absolute value of -3 and 3 is still 3. No matter the negative or not. So that gives us 6 pairs not 3. 
4 0
3 years ago
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