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egoroff_w [7]
3 years ago
9

Given the sequence 8, 16, 32, 64, ..., which expression would give the thirteenth term?

Mathematics
2 answers:
LekaFEV [45]3 years ago
4 0

Answer:

it would be 8 times 2^13

Step-by-step explanation:

Mamont248 [21]3 years ago
4 0
8.2.12 seedsmffkfkrkrkekekekekkejejdhdhbhfbrhdhhfhfufudu
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T- 4t^2 + 2t^3<br> What is the degree of the polynomial?
Eduardwww [97]

Answer:

3rd degree

Step-by-step explanation:

The highest exponent is a 3, meaning this is a 3rd degree polynomial.

4 0
3 years ago
K is the midpoint of PQ, P has
Pachacha [2.7K]

Answer:

Coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q  (x_2,y_2)

We will use the formula of midpoint: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given midpoint K and x_1,y_1 the coordinates of P we need to find x_2,y_2 the coordinates of Q.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\

Now, we can write

-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16

So, we get coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

6 0
3 years ago
Identify the four step used to solve this equation 4(x-7)=2x-6
irinina [24]
1. Solve the bracket 4×x and 4 × -7
4x-28=2x-6
2. Get the x on one side and the numbers on the other so: first +28
4x=2x+22 now -2x
so 2x=22 and now you only need to divide into 2
x=11
3 0
3 years ago
What is the area of a circle with a diameter of 21 centimeters?
sattari [20]
Area of a circle: πr²

Data:
diameter:  21 cm
radius=diameter/2=21 cm/2=10.5 cm

area of this circle: π(10.5 cm)²=110.25π cm²  (≈346.36 cm²)

Answer: area=110.25π cm²
4 0
3 years ago
Read 2 more answers
Diagram shows a section of a bridge between the points A and K. The length of line segment is 640 meters. ∆ABC, ∆CDF, and ∆FJK a
Marta_Voda [28]
AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.

640 / 2 = 320 m= CF
AC & FK= 320/2 =  160 m each

2AC = CF = 2FK
2(160) = 320 = 2(160)

BG = 20 m

20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x

Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
3 0
3 years ago
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