Answer:
Step-by-step explanation:
We would use the t- distribution.
From the information given,
Mean, μ = 2950
Standard deviation, σ = 115
number of sample, n = 25
Degree of freedom, (df) = 25 - 1 = 24
Alpha level,α = (1 - confidence level)/2
α = (1 - 0.98)/2 = 0.01
We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01
The corresponding z score is 2.492
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
2950 ± 2.492 × 115/√25
= 2950 ± 2.492 × 23
= 2950 ± 57.316
The lower end of the confidence interval is 2950 - 57.316 =2892.68
The upper end of the confidence interval is 2950 + 57.316 = 3007.32
The solution is correct.
Answer:
trueeee :) that is my answer
Answer:
14.0
Step-by-step explanation:
$7.50 meal + your 6.5$ tax.
We add those and it will equal 14.00
Answer:
Y = -2X + 7
Step-by-step explanation:
Y = a(x-h)^2 + k
From (h,k) h = 0 k = 7 x = 2 y = 3
3 = a(2-0) + 7
3 = 2a - 0 + 7
Collect like terms
2a = 3 - 7
2a = -4
Divide both sides by 2
2a/2 = -4/2
a = -2
y = a(x-h) + k
y = -2(x-0) + 7
y = -2x + 0 + 7
y = -2x + 7 or
y + 2x - 7 = 0
Answer:
it should be not similar if I'm correct
