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3 years ago

12

Can you please solve for x?

1 answer:

MakcuM [25]3 years ago

6 0

Answer:

The measurement of angle L is given by the expression 180° – 130°. So, angle L measures 50°.

Step-by-step explanation:

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The temperature during the day in Miami was 92 degrees fahrenheit. During the night, the temperature fell 4 degrees fahrenheit.

BigorU [14]

You need to take away 4 degrees from 92.
"Take away" means subtraction.
92 - 4
The answer is option C.

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3 years ago

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Does anybody know how to solve this problem?

Advocard [28]

Answer:BC=68

DE=36

CE=34

Step-by-step explanation:

Since D, E and F are the midpoints, they follow the midpoint theorm which states that "The line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side." As for others, it's just the calculation.

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How do I work this problem out? 7/8-1/4

Tems11 [23]

<span>7/8 - 1/4 = 7/8 - 2/8 = 5/8</span>

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3 years ago

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Help pls , graph and linear equations

drek231 [11]

Answer:

4- -1=3

Step-by-step explanation:

7. m=3 (4,-1)

do the () inside first so

4- -1 = 3

hope this helps for number 7

5 0

3 years ago

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

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3 years ago

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