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alisha [4.7K]
2 years ago
5

Solve for m (- 11/6) + m = -2/9 ​

Mathematics
1 answer:
joja [24]2 years ago
3 0

Answer:

m= -29/18

Step-by-step explanation:

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Find the value of x.
Wewaii [24]

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prob 27

Step-by-step explanation:

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Ricky can ride 17 km on his bike in the same length of time ha can walk 9 km.if his riding speed is 4 kph faster than his walkin
aivan3 [116]
Distance=speed times time
if they take the same time, we cal the time , t

b=bike speed
w=walking speed

bikedistnace=17=bt
walkdistance=9=wt

b is 4 more than w
b=4+w

we have
17=bt
9=wt
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ok so
multiply first equation by 9 and 2nd by 17

153=9bt
153=17wt
set equal
9bt=17wt
divide both sides by t
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36+9w=17w
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vodomira [7]
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Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in
tatuchka [14]

Answer:

The equation representing how old Monique son is \mathbf{a = 2 + \dfrac{8}{21}(q-34)}

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

q(t) = \hat q \times t + q_o

where;

q_o = initial height of Monique's son

\hat q = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

\hat q = 2 \dfrac{5}{8} \ in/yr

\hat q =  \dfrac{21}{8} \ in/yr

Then; from the equation q(t) = \hat q \times t + q_o

34 = \dfrac{21}{8} \times 0 + q_o

q_o = 34\  inches

The height of the son as a function of the age can now be expressed as:

q(t) = \dfrac{21}{8} \times t + 34

Then:

Making t the subject;

q - 34 = \dfrac{21}{8} \times t

t = \dfrac{8}{21}(q-34)

and the age of the son  i.e. ( a (in years)) is:

a = 2 + t

So;

\mathbf{a = 2 + \dfrac{8}{21}(q-34)}

SO;

if q (growth rate) = 50 inches tall

Then;

\mathbf{a = 2 + \dfrac{8}{21}(50-34)}

\mathbf{a = 2 + \dfrac{8}{21}(16)}

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

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