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padilas [110]
3 years ago
11

Given the balanced ionic equation: 2Al(s) + 3Cu2+(aq) → 2Al3+(aq) + 3Cu(s) Compared to the total charge of the reactants, the to

tal charge of the products is 1. less 2. greater 3. the same
Chemistry
1 answer:
ryzh [129]3 years ago
4 0

Answer:

3.- The same

Explanation:

1.- In the reactants you need to calculate the charges that you have:

2 Al(s) = zero, because the aluminum is in it based formed (that mean without charge).

3 Cu2+ = 3 x 2+ = 6+ That is the total positive charges that copper collaborate in this reaction.

2.- Then calculate the charges on the products:

2 Al3+ = 2 x 3+ = 6+ charges from the aluminum.

3 Cu(s) = zero, because the copper in this case is in the base form

3.- In this way, the charges at the begging (6+) and at the end (6+) are the same.

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Answer:

  The mechanism of this reaction i shown on the second uploaded image

The final product of the reaction is shown on the third uploaded image

The hydroxide would be first mixed with the ketone group before the aldehyde is added  

Explanation:

The compound given in the question is 2,2-dimethylpropanal (pivalaldehyde) the structural formula is shown on the first uploaded image

looking at the structurally formula we can see that the hydroxide promoted reaction of this compound would be between the ketone and aldehyde functional group present in this compound in the presence of a hydroxide

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     What happens is that that the OH^- would search for an acidic proton because it is a base and this acidic proton is present in ketone and absent in aldehyde group hence the reason for the first reaction with the ketone group before the aldehyde is added  

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