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Alborosie
3 years ago
14

What is the molecular mass of a gas whose density is 1.25 grams per liter at STP?

Chemistry
1 answer:
satela [25.4K]3 years ago
6 0

STP = standard temperature and pressure

Use the formula:

d = MP/RT

where:

d = density = 1.25 g/L

M = molar mass (unknown)

P = pressure = 1 atm (standard pressure)

R = universal gas constant = 0.8206 L*atm/mol*K

T = temperature = 0C or 293.15 K (standard temperature)

1.25 g/L = M*(1 atm)/(0.08206 L*atm/mol*K)*(273.15 K)

M = 28.0 grams/mol

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\boxed {\boxed {\sf 1076.196 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

q=mc\Delta T

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

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Now we know all the values.

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Substitute the values into the formula.

q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)

Multiply the first two numbers together. The units of grams cancel.

q= 24.459 \ J/ \textdegree C \times 44 \textdegree C

Multiply again. This time, the units of degrees Celsius cancel.

q=1076.196 \ J

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

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