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Misha Larkins [42]
2 years ago
11

K2so4 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m k2so4 solution.

Chemistry
1 answer:
amid [387]2 years ago
8 0

<em>Answer:</em>

  • Conc. of K+ ions = 0.90 M
  • Coc. of SO4∧-2 = 0.45 M

<em>Explanation:</em>

<em>Data Given:</em>

Conc. of H2SO4 = 0.450

As sulphoric acid is a strong electrolyte, it completely dissociate into ions.

H2SO4 ⇆   2K+   +   SO4∧-2

.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.

                      K2SO4  :  K+                                          K2SO4  : SO4∧-2

                          1      =     2                                                   1     =    1

                     0.450   =   2× 0.450 = 0.90                     0.450 =  0.450×1 = 0.450

<em> Result:</em>

Conc. of potassium ion will be 0.90M    

Coc. of sulphate ions will be 0.45 M

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(a) 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) There is no other element present in the compound.

Explanation :

(a) Now we have to determine the masses of C and H in the sample.

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

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We are given:

Mass of CO_2=3.381g

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Molar mass of carbon dioxide = 44 g/mol

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For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.381 g of carbon dioxide, \frac{12}{44}\times 3.381=0.922g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.692 g of water, \frac{2}{18}\times 0.692=0.0769g of hydrogen will be contained.

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(b) Now we have to determine the compound contain any other elements or not.

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