All categories

3 years ago

K2so4 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m k2so4 solution.

Chemistry

1 answer:

amid [387]3 years ago

8 0

Answer:

Conc. of K+ ions = 0.90 M
Coc. of SO4∧-2 = 0.45 M

Explanation:

Data Given:

Conc. of H2SO4 = 0.450

As sulphoric acid is a strong electrolyte, it completely dissociate into ions.

H2SO4 ⇆ 2K+ + SO4∧-2

.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.

K2SO4 : K+ K2SO4 : SO4∧-2

1 = 2 1 = 1

0.450 = 2× 0.450 = 0.90 0.450 = 0.450×1 = 0.450

Result:

Conc. of potassium ion will be 0.90M

Coc. of sulphate ions will be 0.45 M

You might be interested in

Calculate the mass of sodium chloride produced when 5.50 moles of sodium reacts in excess chlorine gas

Dmitry_Shevchenko [17]

The mass of NaCl produced is calculated as below

write the reacting equation

that is 2 Na + Cl2 =2 NaCl

by use of mole ratio between Na :NaCl which is 2 :2 t he moles of NaCl is also = 5.50 moles

mass of NaCl= moles x molar mass

=5.50 moles x58.5 g/mol = 321.75 grams

6 0

4 years ago

Mercury is often released into water bodies with industrial effluents, where it is then converted to the compound form methylmer

sergeinik [125]

This is more to do with Bioaccumulation of mercury, where the mercury is absorbed into the issue of animals, and so animals higher in the food chain consume a lot of tissue matter hence increasing mercury content in their system.

7 0

3 years ago

In the heat equation, what does Q represent? heat required to raise the temperature specific heat of the substance mass of the s

MaRussiya [10]

Answer: heat required to raise the temperature

Explanation: Heat equation is represented as:

$Q= m\times c\times \Delta T$

Q= heat required to raise the temperature

m= mass of the substance

c = heat capacity of substance

$\Delta T={\text{Change in temperature}}$

7 0

4 years ago

Read 2 more answers

Consider the reaction between hydrogen gas and nitrogen gas to form ammonia: 3 H2(g) + N2(g) → 2 NH3(g). What volume of ammonia

TiliK225 [7]

Answer:

$V_{NH_3}=39.6L$

Explanation:

Hello,

By assuming STP conditions (0°C and 1atm), we first compute the reacting moles of both hydrogen and nitrogen as shown below via the ideal gas equation:

$n_{N_2}=\frac{PV}{RT}=\frac{1atm*36.7L}{0.082 \frac{atm*L}{mol*K}*273.15K} =1.64molN_2\\n_{H_2}=\frac{PV}{RT}=\frac{1atm*59.4L}{0.082 \frac{atm*L}{mol*K}*273.15K} =2.65molH_2$

Next, one identifies the limiting reagent by computing the moles of hydrogen that completely react with 1.64mol of nitrogen as follows:

$n_{H_2}^{reacting}=1.64molN_2*\frac{3molH_2}{1molN_2}=4.92molH_2$

In such a way, as there are just 2.65 available moles of hydrogen one states that we have spare nitrogen and the hydrogen is the limiting reagent, thus, the yielded moles of ammonia are computed as:

$n_{NH_3}=2.65molH_2*\frac{2molNH_3}{3molH_2}=1.767molNH_3$

Finally, one computes the required volume in liters as:

$V_{NH_3}=\frac{nRT}{P}=\frac{1.767mol*0.082 \frac{atm*L}{mol*K} *273.15K}{1atm}\\V_{NH_3}=39.6L$

Best regards.

7 0

3 years ago

Consider a hypothetical reaction between A, B, and C that is first order in A, zero order in B, and second order in C.

mr Goodwill [35]

Answer:

(a) Rate = k[A][C]²

(b) If [A] is doubled, then the rate of reaction will be doubled as well.

Explanation:

(a) The rate is equal to the multiplication of a constant and the concentrations of all reactants, each to the power of their order.

Rate = k[A]¹[B]⁰[C]² = k[A][C]²

(b) Looking at the previous equation we can see that if [A] is doubled, then the rate of reaction will be doubled as well.

5 0

4 years ago