Answer:
9/4 (1.75 - 21/4)
=9/4 (1.75 - 5.25)
=2.25 -3.5
= -1.25
I think your f answer is wrong
there should be -1.25
Only the third model shows parallel lines cut by a transversal.
We can solve this problem by using some properties that parallel lines cut by a transversal have. First of all, corresponding angles are congruent, and since the angles in figure 1 are corresponding but not congruent, that means that figure one is out.
In addition, in figure two, alternate exterior and interior angles of parallel lines intersected by a transversal are congruent, so since they are not in the picture, that means that this figure is also out.
Figure three is correct because since those are same side interior angles, they need to be supplementary for those to be two parallel lines intersected by a transversal. Since they do, in fact, add up to 180°, that means that the answer is figure three.
Answer:
a= 6
b = 7
c = 8
d = 7
e = 6
Step-by-step explanation:
Notice that the bike is 6 feet above the ground to start with, so when it starts rolling, the green dot is exactly 6 feet from the ground, which gives a=6
when the distance covered by the bike is 
, (see first red dot in the attached image), the position of the green dot is exactly 1 foot added to 6 ft= 7 feet
so b = 7
when the distance covered is 
, now the green dot would be at the top of the wheel (second red dot in the attached image) which involves adding 2 feet to the original 6 feet. That is: c = 8
when the distance covered is 
, the green dot is at the position of the third red dot in the attached image., that it exactly one foot added to 6 feet = 7 ft which gives the value of d = 7
and finally, when the distance covered is 
. the green dot has completed a full circle and is now again in its lower position (nothing - zero) added to 6 feet = 6ft, giving e = 6.
Answer:
answer 2) 24
Step-by-step explanation:
after the dilation pt D is (8,-32)
after the dilation pt E is (-16,16)
if you use the distance formula for these two points you get 
which simplifies to 24
Why u have so much letters lol what u need help on
