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kolbaska11 [484]
3 years ago
4

What is the exact area of a circle having radius 7 in.?

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
0 0

Answer:

483.1

Step-by-step explanation:

Pie3 years ago
0 0
Soo to get the are you need to follow the formula
Area= pi multiplied by radius (squared)
I don't have the right symbols sorry. Anyways let's continue
First multiply pi which is 3.14 then multiply it to the radius, since the radius is squared then you have to multiply it twice

Solution:
Pi(3.14)xradius that is squared (7 raised to the power of two)
3.14 x 7 x 7= 153.86
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Step-by-step explanation:

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The distance between 1 and -3 is 4. 4 squared is 16.

25+16 = 41

the root of 41 is √41.

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Step-by-step explanation:

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kaheart [24]

Answer:

  First "order of operations" mistake: step 2

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Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

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We expect your answer is supposed to be Step 4.

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