Answer:
Step-by-step explanation:
y=x²-2x-1
and y=-3x+5
x²-2x-1=-3x+5
x²+x-6=0
x²+3x-2x-6=0
x(x+3)-2(x+3)=0
(x+3)(x-2)=0
x=-3,2
when x=-3
y=-3×-3+5=9+5=14
when x=2
y=-3×2+5=-6+5=-1
so solutions are (-3,14) and (2,-1)
Answer:
The student made an error during the distributive property in the second step where they multiplied 0.15 by -0.2 to equal -0.3 when it should have been -0.03.
Step-by-step explanation:
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
I will solve one for you to get you a idea so next u can solve all
To know whether line is tangent toa circle or not we should know that that line is a tangent line of a circle if it intersects circle at single point.
and this will always be perpendicular at radius
so in problem
1)
diameter is given 7.5
and u can see they make a right triangle ABC if that is perpendicular so segment AB is tangent to a circle.
Lets see by applying <span>Pythagorean Theorem
</span>this is method we can say that this is in fact a right triangle
a^2=b^2=c^2
a,b are shorter side c is longer side
(7.5)^2+(8)^2=(17)^2
56.25+64=289
120.25=289
both are not equal so they are not forming right triangle so segment AB is not a tangent line.
You can use the app photo math to get the answer it’s free, hope this helps!
