Answer:
0.0259,0.0406
Step-by-step explanation:
Given that in a poll taken in December 2012, Gallup asked 1006 national adults whether they were baseball fans: 48% said they were. Almost five years earlier, in February 2008, only 35% of a similar-size sample had reported being baseball fans.
a) p is the proportion of national adults who are baseball fans.
b) For 2012 poll, p=0.48
Std error = 
Margin of error at 90% = 1.645 * std error
= 0.0259
c) Margin of error is the admissible limit on either side of the mean where the sample mean can lie
d) Margin of error would be larger for 99% because critical value 2.58 >1.645
e) Margin of error 99% = 
1. 7,028 2. 7,208 3. 7,288 4. 7,828 5. 7,088 6. 2,570 7. 2,507 8. 2,577 9. 2,057 10. 2,077 11. 9,009 12. 9,900 13. 9,090 14. 9,099 15. 9,999
Answer: EDIT: the answer is 4 3/12
Step-by-step explanation:
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