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mariarad [96]
3 years ago
14

Write an exponential function to model the following situation.

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

For 15 years - 110,000(1.04)^{15}

After 15 years - 110,000(1.04)^{x+15}

Step-by-step explanation:

We have that,

Initial population is 110,000 which grows by the rate 4% i.e. 0.04 for 15 years.

Since, the exponential growth is given by P(1+r)^{x},

where P is the initial population, r is the rate of interest and x is the number of years.

Thus, the required population is 110,000(1+0.04)^{15} i.e.  110,000(1.04)^{15}.

Moreover, after 15 years i.e. x+15 years, the population will be 110,000(1.04)^{x+15}.

Thus, the population after 15 years is 110,000(1.04)^{x+15}.

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Help! Please!!! I seriously need this!!!!!
Kitty [74]

Answer:

it's related by product of 5/3 and directly proportional

3 0
2 years ago
A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an
liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute  = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

<u>when the angle is 30 degrees</u>

tan(30) = \frac{6000}{d1}

d1   = \frac{6000}{tan(30)}

d1 = \frac{6000}{0.577}

d1 = 10392.3 meters

<u>when the angle is 60 degrees</u>

tan(60) = \frac{6000}{d2}

d2  = \frac{6000}{tan(60)}

d2  = \frac{6000}{1.732}\\

d2 = 3464.1 meters

<u>distance travelled by aircraft in 1 min is  </u>

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

<u>Now converting to m/sec</u>

=>\frac{6928.2}{60}

=>115.47 m/sec

4 0
3 years ago
(7,5), (r,9) m=6<br><br> What is r?
Igoryamba

Answer:

The answer is that r = 7/6

Step-by-step explanation:

Given point: (7, 5)

Given slope: m = 6

Use the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 6(x - 7)

y - 5 = 6x - 7

y = 6x + 2

Now, find r for the point (r, 9) by substitution:

9 = 6x + 2

6x + 2 = 9

6x = 7

x = 7/6

Proof:

y = 6x + 2

f(x) = 6x + 2

f(7/6) = 6(7/6) + 2

= 42/6 + 2

= 7 + 2 = 9, giving (7/6, 9). r = 7/6

Hope this helps! Have a great day!

4 0
3 years ago
If f(x)= x2 + 2 and g(x)= 2x-1, find (f ° g)(5).
valentinak56 [21]
I hope this helps you

4 0
3 years ago
Math help @LIEMONDER
klio [65]
First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2

insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3

(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs

insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults

insert adults into II:
33-8=childs
25=childs

so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6

so it's the last option

question 8)
I: x+y=12
II: x-y=6

subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3

insert y into I:
x+3=12
x=9

(9,3)

question 9)
I: x+y=6
II: x=y+5

if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6

which is the second option :)
5 0
2 years ago
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