This is what it would look like if your starting point was at (-1,-5)
Answer:
42
Step-by-step explanation:
<u>Answer:</u>
There are infinite solutions to the system of equations given
<u>Solution:
</u>
The given equations given are,
------ (i)
---- (ii)
Now putting the value of (i) in (ii) we get,





So, there are <em>infinite solutions</em> to the system.
900,000 + 60,000 + 60
hope this helps
This is basically a system of 3 linear equations with variables x, y and c.
x+y = 6...................................(1)
5x/3 + y = c .........................(2)
2y = c-4x .............................(3)
(2)-(1)
5x/3-x +y-y = c-6 => 2x/3 = c-6 => x = (3/2)(c-6)=3c/2-9 ..............(4)
(3) - 2(2)
2y-2y - 10x/3 = c -4x -2c
=> 2x/3 = -c
=> x = -(3/2)c.............................................................................................(5)
Finally, equate (4) & (5) to get
3c/2-9 = -3c/2
=>
3c = 9
=> c=3