Well, bearing in mind that, a year has 12 months, so 18 months is really just 18/12 of a year, or 3/2 a year, then
Answer:
B. 40 meters
Step-by-step explanation:
— Estimating
The rectangle enclosing the path has sides of length 9 m and 14 m, so its perimeter is 2(9+14) = 46 m. The distance covered will be shorter than that.
The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.
Only one answer choice fits in the range 37 < d < 46.
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— Detailed calculation
The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.
The circuit length is ...
AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters
Since the change is to x, it will be a horizontal transformation.
When x is multiplied by a factor between 0 and 1, it stretches the function horizontally.
In this case, it stretches the function by a factor of 2 horizontally.
Answer:Definition area"? Do you mean the "natural domain" of the function- the region in which the formula is defined? In order that a number have a square root that number must be non-zero.
Step-by-step explanation:Here, we must have x−1x≥0.
If x is positive, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, both x- 1 and x+ 1 must have the same sign: either x-1> 0 and x+ 1> 0 or x- 1< 0 and x+ 1< 0. The first pair of inequalities is true for x> 1 and the second for x< -1. Since "x is positive", we must have x> 1.
If x is negative, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, x- 1 and x+ 1 must have opposite signs: x+ 1> 0 and x- 1< 0 or x- 1<0 and x- 1> 0. The first pair is true for −1≤0≤1. The second pair are never both true. Since "x is negative" we must have −1≤x≤0.
Of course, we also cannot divide by 0 so x= 0 is not in the domain. The domain is the union of the two separate sets:{x|−1≤x<0}∪{x|x>1}.
Hope That Helps!
