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3 years ago

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A family took a road trip that required them to drive 560 miles. Mom, Dad, and their oldest son, Alex, took turns driving. Dad d

rove twice as far as mom and 60 miles more than Alex. How far did Dad drive

1 answer:

never [62]3 years ago

4 0

Answer: 248 miles

Step-by-step explanation: The equation is x+2x+2x-60 where x is the mom and 2x is Dad and since dad drove 60 miles more than alex then Alex drove 60 miles less than dad so 2x -60 is alex. Altogether x+2x+2x-60 = 560 total miles driven and solved is x = 124 however x is just the mom. The dad drove twice as much so we have to double 124 or multiply by 2 to get the amount The dad drove which is 124*2= 248 miles

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Triangle ABC with vertices A(-4, 2), B(4,7), and

alex41 [277]

Step-by-step explanation:

A(-4,2)=A'(-4,-2)

B(4,7)=B'(4,-7)

C(5,1)=C'(5,-1)

4 0

3 years ago

For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of

mihalych1998 [28]

Answer:

$V=196in^3$

Step-by-step explanation:

The volume of a pyramid is:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height (the perpendicular measurement between base and highest point, not the slant height)

Since the base is a square, the area is given by:

$A_{b}=l^2$

where $l$ is the length of the side: $l=8in$ , thus:

$A_{b}=(8in)^2\\A_{b}=64in^2$

Now we need to find the height, for this we use the right triangle that forms with half of a square side (8in/2 = 4in), the slant height (10in), and the height.

In this right triangle, the slant height is the hypotenuse, the leg 1 is the unknown height, and leg 2 is half of the square side.

Using pythagoras:

$hypotenuse^2=leg1^2+leg2^2$

substituting our values, and indicating that leg 1 is height h:

$(10in)^2=h^2+(4in)^2$

$100in^2=h^2+16in^2$

and solving for the height:

$h^2=100in^2-16in^2\\h^2=84in^2\\h=\sqrt{84in^2}\\ h=9.165in$

and finally we calculate the volume using this height and the area of the base:

$V=\frac{A_{b}h}{3}$

$V=\frac{(64in^2)(9.165in)}{3} \\V=195.5in^3$

rounding to the nearest cubic inch: $V=196in^3$

4 0

3 years ago

When Theresa walks at a pace of 88 steps per minute, it takes her 90 minutes to walk the trail. If she alters her pace to 33 ste

jarptica [38.1K]

Answer: 33 minutes

Step-by-step explanation:

Hi to answer this question we have to write a proportion

Speed rate = 88 step per minute

Time = 90 minutes

So, the proportion is 88 step/min / 90 minutes

For 33 steps per minutes = 33 / x minutes

88/90 = 33/x

solving for x:

x= 33/ (88/90)

x = 33.75 = 33 minutes.

Feel free to ask for more if needed or if you did not understand something.

5 0

3 years ago

Which of the following equations is modeled by the graph.

Sergio [31]

Answer:

a = 50t

Step-by-step explanation:

The graph goes through (0,0) so the y intercept is 0

a=5t

a=50t

a=50 + t not it

a=10t

The slope is y/x since the y intercept is 0

m = 50/1 = 50

The equation for the line is

y = 50x+0

y = 50x

Using the variables given

a = 50t

5 0

3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

3 years ago