How long will it take me to drive 175 miles at a speed of 25 miles per hour?

Brandy is making a peach pie for her grandmother for christmas. the diameter of the pie is 12 in. if three-fourths of the area o

Mariulka [41]

Roughly 84 square in

4 0

2 years ago

Julio says "If you subtract 13 from my number and multipy the difference by -3 the result is -45" what is Julio's number

ICE Princess25 [194]

Answer:28

Step-by-step explanation:

Julio's number is x

(X-13)*-3=-45

Divide by -3

X-13=15

Add13 to both sides

x=28

6 0

3 years ago

If theres 3 apples and you take 2 away, how many do you have?

Degger [83]

The answer depends on the perspective; however, this question is often meant to be a "trick question"; with the answer being: 2 (two) apples!
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The rationale behind this answer is that if there are three apples, but you "take 2 away" you now have "2" apples, because YOU are the one who "took away the 2 apples"—so presumably, YOU have the "2 apples" that YOU "took away"!

5 0

3 years ago

Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )

DedPeter [7]

(a) First find the intersections of $y=e^{2x-x^2}$ and $y=2$ :

$2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}$

So the area of $R$ is given by

$\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx$

If you're not familiar with the error function $\mathrm{erf}(x)$ , then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line $y=1$ with $y=e^{2x-x^2}$ .

$1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2$

So the area of $S$ is given by

$\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx$
$\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx$

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve $y=e^{2x-x^2}$ and the line $y=1$ , or $e^{2x-x^2}-1$ . The area of any such circle is $\pi$ times the square of its radius. Since the curve intersects the axis of revolution at $x=0$ and $x=2$ , the volume would be given by

$\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx$

5 0

3 years ago

Pls help

BaLLatris [955]

Answer:

If you go to fill up your car, the amount of gasoline in your tank influences how much you pay. The amount is a volume calculation, regardless of whether you fill up with gallons or liters of gasoline or other fuels. On a lesser scale, when filling a gas can to transfer to another vehicle or utilize the gas to power another device, volume is used to calculate the amount needed.

Hope this helps!

4 0

2 years ago