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rosijanka [135]

3 years ago

11

Someone please help me

1 answer:

nadezda [96]3 years ago

4 0

Answer:

Quadrilateral ABCD is a rectangle (more specifically a square)

Quadrilateral WXYZ is not a rectangle

Step-by-step explanation:

A rectangle is a quadrilateral with four straight sides, two sets of parallel sides, and four right angles. Quadrilateral ABCD is a rectangle because it fits all of the criteria. Quadrilateral WXYZ is not a rectangle because it does not have four straight sides or four right angles.

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Which of the following is a counterexample to the statement “All even numbers are divisible by 4”? 2 x 2 = 4 7 is not divisible

Naily [24]

10 is not divisible by 4

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A regression equation was estimated as = –100 + 0.5x. if x = 20,the predicted value of y is _____.

ratelena [41]

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If an item costs $45 and we must pay 6% sales tax, how much will we pay for the item?

Gennadij [26K]

$47.70

$45 with 6% sales tax

6%=.06

To find total amount multiply by 1.06 or multiply by .06 and that is tax amount and then add it to the $45

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Any questions feel free to ask. Have a great day!

4 0

3 years ago

Read 2 more answers

The sum of two integers is 33. The larger is 6 more than twice the smaller. Find the two

grandymaker [24]

Answer:

24 and 9

Step-by-step explanation:

Hi there!

Let x be equal to the larger integer.

Let y be equal to the smaller integer.

<u>1) Construct equations</u>

$x+y=33$ (The sum of two integers is 33)
$x=6+2y$ (The larger is 6 more than twice the smaller)

<u>2) Solve for one of the integer</u>

Isolate x in the first equation

$x+y=33\\x=33-y$

Plug the first equation into the second

$33-y=6+2y$

Combine like terms

$33-6=2y+y\\27=3y\\9=y$

Therefore, the smaller integer is 9.

<u />

<u>3) Solve for the other integer</u>

$x+y=33$

Plug in y (9)

$x+9=33\\x=33-9\\x=24$

Therefore, the larger integer is 24.

I hope this helps!

4 0

3 years ago

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Calculate: 1/1x3+1/3x5+…+1/47x49

shtirl [24]

Answer:

24/49

Step-by-step explanation:

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2 years ago