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adoni [48]
2 years ago
12

Identify each coefficient for 3m. this question is on my homework what Is the answer?

Mathematics
1 answer:
Minchanka [31]2 years ago
4 0

Answer: 3

Step-by-step explanation: The number in front of your variable is called your coefficient so we say that 3 is the coeficient.

Make sure to understand that a variable

is just a letter that represents any number.

You might be interested in
The solution set of this inequality?<br><br> 11q+5≤49
sineoko [7]

Subtract 5 from both sides.

49 - 5 = 44

11q ≤ 44

Divide both sides by 11.

44/11 = 4

q ≤ 4

3 0
3 years ago
Read 2 more answers
I NEED HELP QUICK!
ivanzaharov [21]
<h2><u>Answers:</u></h2>

a. What properties do these shapes have in common?

The square, the rectangle and the rhombus are in the <u>quadrilaterals</u> group (<u>shapes or figures with four sides</u>) and in the <u>parallelogram</u> sub-group (shapes or figures with four sides in which <u>opposite sides are parallel</u>).  

In other words,

<h2>what these three shapes have in common is that they are Parallelograms.</h2>

Hence, they have the same <u>properties of a parallelogram</u>, such as:

1. Opposite sides parallel and with the same length

2. Opposite angles are congruent (<u>equal angles</u>, or angles with the same value)

3. Consecutive angles are supplementary (<u>angles that add up to 180°</u>)

Also the general <u>properties of a quadrilateral</u>:

1. It has four sides

2. It is a 2-dimensions shape

3. It is a closed figure

4. It has four corners (<u>called vertices</u>), and four interior angles, as well.

5. The sum of their four interior angles is 360º

b. How are these two shapes different?

In this case we are going to talk about <em>the differences between the Rectangle and the Rhombus</em>, because the square is a special case of both.

Now, the <u>differences between the Rectangle and the Rhombus</u> are:

1. In the Rectangle only the opposite sides are of the same length, while in the rhombus all of its sides are of the same length.

2. If you trace two diagonal lines inside the Rectangle, they will have the same length. But if you trace two diagonal lines inside the Rhombus they will have different lengths.

3. When the two diagonals in the Rectangle are intersected, they are not perpendicular, but in the case of the Rhombus they are perpendicular (both lines form an angle of 90º)

4. All the angles of the rectangle have the same value: 90º. But in the case of the rhombus only the opposite angles have the same value.

c. What conclusion can you make about the square, rhombus and rectangle?

These three shapes belong to the parallelogram group (which is also part of the quadrilaterals group). They have a lot of things in common for being quadrilaterals, with some differences related to their own shape.

The square is a special case of these three figures, is a rhombus (four equal sides) and a rectangle (four equal 90º angles), as well.


5 0
3 years ago
PLEASE HELP ASAP!!!! Thanks!!
tino4ka555 [31]

Answer:

1.2 cm

Step-by-step explanation:

Quadrilateral circumscribing a circle is a quadrangle whose sides are tangent to a circle inside it (see attached diagram).

The area of circumscribed quadrilateral is

A=p\cdot r,

where p=\dfrac{a+b+c+d}{2} is semi-perimeter and r is radius of inscribed circle.

In your case, A=12\ cm^2

If a quadrilateral is circumscribed over the circle, then the sum of opposite sides is equal, so

a+c=b+d=10\ cm,

so

P=10+10=20\ cm\\ \\p=\dfrac{20}{2}=10\ cm

Now

12=10\cdot r\Rightarrow r=\dfrac{12}{10}=1.2\ cm

8 0
3 years ago
1. Solve the given linear equations for 'x':
postnew [5]

i ) 3(2x - 3) = 4(2x + 4)

6x - 9 = 8x +1 6 \\  \\ 6x - 8x = 16 + 9 \\  \\  - 2x = 25 \\  \\ x =   - \frac{25}{2} .

ii )2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)

2x + 4 + 5x + 25 = 4x - 32 + 2x - 4 \\  \\ 7x + 29 = 6x - 36 \\  \\ 7x - 6x =  - 36 - 29 \\  \\ x =  - 65.

<h2>----------------------</h2>

2. 3x /4 - 7 /4 = 5x + 12

\frac{3x}{4}  -  \frac{7}{4}  = 5x + 12 \\  \\  \frac{3x}{4}  - 5x = 12 +  \frac{7}{4}  \\  \\  \frac{3x - 20x}{4}  =  \frac{48 + 7}{4}  \\  \\  \frac{ - 17x}{4}  =  \frac{55}{4}

cancel 4 from both sides

- 17x = 55 \\  \\ x =  \frac{ - 17}{55} .

<h2>-------------------</h2>

3. x +7 - 8x/3 = 17/6 - 5x/8

x + 7 -  \frac{8x}{3}  =  \frac{17}{6}  -  \frac{5x}{8}

put x = 4

4 + 7 -  \frac{ 8\times 4}{3}  =  \frac{17}{6}  -  \frac{5 \times 4}{8}  \\  \\ 11 -  \frac{32}{3}  =  \frac{17}{6}  -  \frac{20}{8}  \\  \\  \frac{33 - 32}{3}  =  \frac{68 - 60}{24}  \\  \\  \frac{1}{3}  =  \frac{8}{24}  \\  \\  \frac{1}{3}  =  \frac{1}{3} .

L.H.S. = R.H.S.

<h2>--------------------</h2>

4. Let 3 consecutive integers : x , x+1 , x+2

As per the question : 2x + 3(x+1) + 4(x+2) = 56

9x + 11 = 56

Transpose 11 to RHS

9x = 45

Divide both sides by 9

x = 5 ,

x + 1 = 5 + 1 = 6

x + 2 = 5 + 2 = 7

Numbers are 5 , 6 and 7 .

<h2>-----------------------</h2>

5. Let the age of Jane’s younger sister is x.

Age of Jane will be x + 6

As per the question, after 10 years the sum of their ages will be 50.

After 10 years,

age of Jane = x + 16

age of her younger sister = x + 10

Therefore,

x + 16 + x +10 = 50

2x + 26 = 50

2x = 24

x = 12

Thus, the present age of Jane’s younger sister is 12 years.

And of Jane’s is 12 + 6 = 18 years.

<h2>---------------------</h2>

6. Let the breadth of rectangular swimming pool be x metres.

Then, its length = (2x + 2) metres.

We know that the Perimeter of a rectangle

= 2(Length + Breadth)

= 2(2x + 2 + x) = 6x + 4

According to the given condition, we have

6x + 4 = 154

6x = 154 − 4

6x = 150

[Dividing both sides by 6]

x = 25

Thus, breadth = 25 m and

length = 25 × 2 + 2 = 52 m .

<h2>---------------------</h2>

7. Let the digit in ten's .

Place be x and the digit in the one's place be y.

x − y = 5 ⟶ (i)

Two digit number = 10x + y

Two digit after reversing the digits = 10y + x

According to question ,

10x + y + 10y + x = 99

11x + 11y = 99

x + y = 9 ⟶ (ii)

On adding (i) and (ii),

2x = 14

x = 7

Putting the value of x in equation (i)

x − y = 5

y = 2

Number = 10x + y

=72 .

<h2>-----------------------</h2>

8. Let the speed of the steamer in still water be x km/h.

Then , the speed downstream = (x+2) km/h

and the speed upstream = (x−2) km/h

Given , distance covered in 4 hours downstream = distance covered in 5 hours upstream

4(x + 2) = 5(x − 2)

4x + 8 = 5x − 10

4x − 5x = − 10 − 8

[Transposing 5x to LHS and 8 to RHS]

−x = −18 or x = 18 km/h .

<h2>-----------------------</h2>

9. Let the number of notes of different denomination be x.

∴ Numbers of Rs 100 notes , 50 notes and Rs 10 notes will be 2x , 3x and 5x respectively.

Amount of 100 Rs notes ⇒Rs 100 × 2x = 200x

Amount of 50 Rs notes ⇒Rs 50 × 3x = 150x

Amount of 10 Rs notes ⇒Rs 10 × 5x = 50x

As per the question

Total amount = 400000

200x + 150x + 50x = 400000

400x = 400000 , x = 1000

No of Rs 100 notes = 2x = 2 × 1000 = 2000

No of Rs 50 notes = 3x = 3 × 1000 = 3000

No of Rs 10 notes = 5x = 5 × 1000 = 5000 .

<h2>------------------------</h2>

10. Let the age of the man be x

Then age of his son becomes (x − 24)

2 years later from now,

Age of man will be = x + 2

and age of his son will be = (x − 24 + 2) = x − 22

According to question,

2(x − 22) = x + 2

i.e., 2x − 44 = x + 2

i.e., x = 46

Therefore ,

Present age of man = 46 years

And present age of his son = 46 − 24 = 22 years .

4 0
2 years ago
90 out of 120 students in your grade are girls at your school. What percentage are boys?
sesenic [268]
30% Bc there are 30 boys and 90 girls or it’s 10% boys
7 0
3 years ago
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