Question

Determine the [OH−]

Answer 1

Answer:

Explanation:

[H+] = 4.7 x 10⁻⁵ M

[H+][OH⁻] = 10⁻¹⁴

[OH⁻] = $\frac{10^{-14}}{4.7\times 10^{-5}}$

= .2127 x 10⁻⁹ M

pH = - log[H+]

= - log [ 4.7 x 10⁻⁵]

= - log4.7 + 5

= 4.328

pH + pOH = 14

pOH = 14 - pH

= 14 - 4.328

= 9.672