Answer:
16 table each table seats 22 so 16 * 22 = 352
Step-by-step explanation:
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Step-by-step explanation:
p²-5p-14=0
p²-7p+2p-14=0
p(p-7)+2(p-7)=0
(p-7)(p+2)=0
either,
p-7=0
p=7
or,
p+2=0
p = -2
hope it helps.
Answer:
if its a multiple choice its A!
Step-by-step explanation:
These customers use at least 4,970 gallons but no more than 8,970 gallons of water per month.