<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
x²+y²-2x-6y-5=0
x²-2x+y²-6y=5
x²-2x+1+y²-6y+9=5+1+9
(x-1)²+(y-3)²=15
(x-1)²+(y-3)²=(V15)²
-> centre of the circle: C(-1,-3)
-> radius of the circle: V15
27h / 3h = (9 x3h) / (1x3h) = 9