How old is Neil if 200 reduced by 2 times his age is 144?

A square field has a perimeter of 48cm find the area of the field

BabaBlast [244]

Answer:

2,304

Step-by-step explanation:

u multiply one length by it widgth so 48 x 48

7 0

2 years ago

Read 2 more answers

The graph shows the relationship between the amount of time that a backpacker hikes and the distance traveled.

julsineya [31]

Answer:

The points represent that 5 miles were hiked in 3 hours.

Step-by-step explanation:

So, lets go over what we need to know.

The x coordinates is the time.

The y coordinates is the miles.

We have (3, 5)

This is (x, y)

x = 3, and y = 5. Considering what we know above, the time is 3 hours, and the miles is 5.

To fill in the boxes, it asks "Blank miles are hiked in blank hours"

We know 5 miles are hiked in 3 hours.

So the fill in for the first part is 5, and the fill in for the second part is 3.

Hope this helps!

3 0

2 years ago

20 POINTS , ALSO GIVING BRAINLIEST , PLEASE HURRY !!

liq [111]

Answer:

.5236

Step-by-step explanation:

Formula for sphere volume:

V = $\frac{4}{3} \pi r^{3}$

substiture 0.5 for r:

$\frac{4}{3} \pi 0.5^{3}$ = .5236

5 0

2 years ago

How to multiply numbers with exponets and different bases

o-na [289]

When the bases are diffenrent and the exponents of a and b are the same, we can multiply a and b first:
a n ⋅ b n = (a ⋅ b) n
Example:
32 ⋅ 42 = (3⋅4)2 = 122 = 12⋅12 = 144

When the bases and the exponents are different we have to calculate each exponent and then multiply:
a n ⋅ b m
Example:
32 ⋅ 43 = 9 ⋅ 64 = 576

5 0

3 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago