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Harrizon [31]
4 years ago
13

What is the best reason to delete Internet browsing history on a regular basis? to solve a computer hardware problem to protect

the computer and keep it safe to prevent anyone from discovering it to fix a keyboard with sticky keys
Computers and Technology
2 answers:
konstantin123 [22]4 years ago
7 0

Answer:

A (to solve a computer hardware problem)

xz_007 [3.2K]4 years ago
3 0

The correct answer is A) To solve a computer hardware problem


This is the only reasonable answer from the list. Besides that computer history can cause viruses and slow down the browser speed.

I hope this helps and have a good evening dear :)

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Write a program to simulate the design process of the course. First, create a struct for the course which consists of following
Dmitry [639]

Answer:

#include <iostream>

using namespace std;

struct Course

{

int courseNumber;

int courseStartDate;

int courseHours;

int lecturerId;

};

struct Lecturer

{

int lecturerId;

int officeHours;

Course courseTeaching[2];

};

struct Student

{

int studentId;

Course coursesTaken[2];

};

int main()

{

Course courseObj1, courseObj2, courseObj3;

courseObj1.courseNumber = 1000;

courseObj1.courseStartDate = 20200107;

courseObj1.courseHours = 2;

courseObj1.lecturerId = 100;

courseObj2.courseNumber = 1100;  

courseObj2.courseStartDate = 20200113;

courseObj2.courseHours = 4;

courseObj2.lecturerId = 200;

courseObj3.courseNumber = 1200;

courseObj3.courseStartDate = 20200203;

courseObj3.courseHours = 4;

courseObj3.lecturerId = 100;

Lecturer lecturerObj1, lecturerObj2;

lecturerObj1.lecturerId = 100;

lecturerObj1.officeHours = 2;

lecturerObj1.courseTeaching[0] = courseObj1;

lecturerObj1.courseTeaching[1] = courseObj3;

lecturerObj2.lecturerId = 200;

lecturerObj2.officeHours = 2;

lecturerObj2.courseTeaching[0] = courseObj2;

Student student;

student.studentId = 2000;

student.coursesTaken[0] = courseObj1;

student.coursesTaken[1] = courseObj3;

cout << "1. Lecturer ID: " << lecturerObj1.lecturerId << "\tOffice Hours: " << lecturerObj1.officeHours << endl;

for(int i = 0; i < 2; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj1.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj1.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj1.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj1.courseTeaching[i].lecturerId << endl;

cout << "\n2. Lecturer ID: " << lecturerObj2.lecturerId << "\tOffice Hours: " << lecturerObj2.officeHours << endl;

for(int i = 0; i < 1; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj2.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj2.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj2.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj2.courseTeaching[i].lecturerId << endl;

int courseNumber;

cout << "\n Enter the course number: ";

cin >> courseNumber;

int index = -1;

int len = sizeof(student.coursesTaken) / sizeof(student.coursesTaken[0]);

int totalHours = 0;

for(int i = 0; i < len; i++)

{

if(student.coursesTaken[i].courseNumber == courseNumber)

{

totalHours += student.coursesTaken[i].courseHours;

}

}

if(totalHours == 0)

cout << "\n Student is not registered to this course!\n";

else

cout << "\nStudent " << student.studentId << " needs " << totalHours << " hours per week of this course.\n";

return 0;

}

Explanation:

  • Create the 3 objects of Course class and set their properties respectively.
  • Create the 2 objects of Lecturer class and set their properties respectively.
  • Create an object of Student class and set their properties respectively.
  • Run a for loop and check whether the current courseNumber is already added and then increment the total number of hours for that course.
  • Finally check if totalHours is equal to 0 or not and then display the suitable message accordingly.
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8 0
3 years ago
Read 2 more answers
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