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3 years ago

The roots of y in the equation y^2-2y=-9/2 are

1 answer:

3 0

Simplify y^2y to y^3
Y^3=9/2
Take the cube root of both sides
Y=3(9/2)
Use the divisions distributive property
Y=^3(9)/3(2)
Rewrite 9 as 3^2
Y=3(3^2)/(3(2)
Use this rule (x^a)^b=^ab
Y=3(2/3)/3/2

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Step-by-step explanation:

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3 years ago

Point T is at (-3, 8). What are the coordinates of T' after R(y-axis) o R(x-axis)?

Whitepunk [10]

Given:

Point is T(-3,8).

To find:

The coordinates of T' after $R(y-axis)\circ R(x-axis)$ .

Solution:

We know that, $R(y-axis)\circ R(x-axis)$ means the figure reflected across the x-axis then reflected across y-axis.

If a figure reflected across x-axis, then

$(x,y)\to (x,-y)$

$T(-3,8)\to T_1(-3,-8)$

If a figure reflected across y-axis, then

$(x,y)\to (-x,y)$

$T_1(-3,-8)\to T'(-(-3),-8)$

$T_1(-3,-8)\to T'(3,-8)$

Therefore, the required point is T'(3,-8).

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3 years ago

The output is eight less than the input

horsena [70]

x | y
——-
-10|-18
-9 |-17
-8 |-16
-7 |-15
-6 |-14
-5 |-13
-4 |-12
-3 |-11
-2|-10
-1 | -9
0 | -8
1 | -7
2 |-6
3 | -5
4 | -4
5 | -3
6 | -2
7 | -1
8 | 0
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