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kompoz [17]
3 years ago
6

a triangle is inscribed in a semicircle one angle measures 60 degrees what is the measure of the other two angles

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0
If I am understanding it correctly, it would be 15, because it has to measure up to 90 degrees so it would be 60+15+15=90
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Please help me!!! I can’t sleep until it’s done !!
xxTIMURxx [149]

Answer:

Where’s the question, send it and let me try

Step-by-step explanation:

6 0
3 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
For second answer how do you get it plz urgent plz
inna [77]

Step-by-step explanation:

Complete question is attached.

Answer:

a) ED = 6.5 cm

b) BE = 14.4 cm

Step-by-step explanation:

From the triangle, we are given the following dimensions:

AB = 20 cm

BC = 5 cm

CD = 18 cm

AE = 26 cm

We are asked to find length of sides ED and BE.

a) Find length of ED.

From the triangle Let's use the equation:

\frac{AB}{BC} = \frac{AE}{ED}BCAB=EDAE

Cross multiplying, we have:

AB * ED = AE * BC

From this equation, let's make ED subject of the formula.

ED = \frac{AE * BC}{AB}ED=ABAE∗BC

Let's substitute figures,

ED = \frac{26 * 5}{20}ED=2026∗5

ED = \frac{130}{20} = 6.5ED=20130=6.5

Therefore, length of ED is 6.5 cm.

b) To find length of BE, let's use the equation:

\frac{AB}{AC} = \frac{BE}{CD}ACAB=CDBE

Cross multiplying, we have:

AB * CD = AC * BE

Let's make BE subject of the formula,

BE = \frac{AB * CD}{AC}BE=ACAB∗CD

From the triangle, length AC = AB + BC.

AC = 20 + 5 = 25

Substituting figures, we have:

BE = \frac{20 * 18}{25}BE=2520∗18

BE = \frac{360}{25} = 14.4BE=25360=14.4

Therefore, length Of BE is 14.4cm

I JUST SO THAT IN INTERNET:)

4 0
3 years ago
17 times 14 times 123
LUCKY_DIMON [66]

Answer:

29274

Step-by-step explanation:

Because 17*14=238 and 238*123=29274

8 0
3 years ago
Read 2 more answers
How do you solve (7x + 5) - (3x + 2)
Korolek [52]

Answer:

x = 0.75

Step-by-step explanation:

Simplifying

(7x + -5) + -1(3x + -2) = 0

Reorder the terms:

(-5 + 7x) + -1(3x + -2) = 0

Remove parenthesis around (-5 + 7x)

-5 + 7x + -1(3x + -2) = 0

Reorder the terms:

-5 + 7x + -1(-2 + 3x) = 0

-5 + 7x + (-2 * -1 + 3x * -1) = 0

-5 + 7x + (2 + -3x) = 0

Reorder the terms:

-5 + 2 + 7x + -3x = 0

Combine like terms: -5 + 2 = -3

-3 + 7x + -3x = 0

Combine like terms: 7x + -3x = 4x

-3 + 4x = 0

Solving

-3 + 4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.

-3 + 3 + 4x = 0 + 3

Combine like terms: -3 + 3 = 0

0 + 4x = 0 + 3

4x = 0 + 3

Combine like terms: 0 + 3 = 3

4x = 3

Divide each side by '4'.

x = 0.75

Simplifying

x = 0.75

6 0
2 years ago
Read 2 more answers
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