step 1
Find the <span>average growth per year of the populations of rabbits farm A
</span><span>Over the first 2 years
for t=0
</span>numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
<span>Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
</span><span>the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
</span>the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Answer:
one forty fifth times five equals one ninth
Step-by-step explanation:
In division, the number being divided is the dividend or numerator, the denominator is the number we use to do the division while the result is the quotient and there may be a reminder.
For example, if
a/b = c
then
a = b * c
hence
1/9 ÷ 5
= 1/9 * 1/5
= 1/45
This means that
1/45 * 5 = 1/9
Hence the related multiplication equation related to the division equation one ninth ÷ 5 is one forty fifth times five equals one ninth
For deck,
Length = 2x + 1
Width = 5x + 2
For pool,
Length = 2x
Area of deck including pool = (2x + 1)(5x + 2) = 10x^2 + 4x + 5x + 2 = 10x^2 + 9x + 2
Area of pool = 2x * 2x = 4x^2
Area of only the deck = 10x^2 + 9x + 2 - 4x^2
= 6x^2 + 9x + 2
Answer:
3/2v
Step-by-step explanation:
v+1/2 is 1.5v or 3/2v.
Hope this helps :D