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3 years ago

35+-20+-5 What is the answer?? Worth 10pts...

1 answer:

3 0

$35 + - 20 + - 5$

If two signs are different they make a negative, if two signs are the same, they make a positive:

$35 - 20 - 5$
$10$

Hope this helps!

You might be interested in

2/5;0.5 tell whether each pair shows equivalent number

Georgia [21]

2/5= 40%, so no, they are not equivalent numbers,

4 0

3 years ago

if a rug was 5 times as long as thia record sheet, how long would it be? measure the length of this record sheet in centimeters.

vlada-n [284]

Answer:

If a rug was 5 times as long as this record sheet. The length of this record sheet in centimeters is 100x centimeter

Solution:

Given that a rug was 5 times than the record sheet.

Let assume the length of the record sheet = x units

Then from given information,

Length of the rug = 5x units

Conversion of measure of record sheet in centimeter completely depends upon in which unit the length is given.

Suppose the given length is in meters, than need to multiply the given length by 100 to get the length in centimeter that is

x meter = $x \times 100$ = 100x cm

Conversion factor will change accordingly to the unit of given length which needs to be convert into centimeter.

4 0

3 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

Left part:

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Right part:

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago

235,000 rounded nearest hundred thousand

Gelneren [198K]

I would say 200,00 because if you see it like a roller coaster
down 1234
up 6789
Hope I helped ;-)

7 0

3 years ago

Read 2 more answers

It takes 300 newtons of force and a distance of 20 meters for a moving car to come to stop. How much work is a one n the cart?

IceJOKER [234]

Work done on cart
:

W
=
6000

J
Kinetic energy of cart
:

E
K
=
6000

J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300

N

⋅
20

m
⇒
W
=
300

kg

⋅

m s
−
2

⋅
20

m
⇒
W
=
300
⋅
20

kg

⋅

m
2

s
−
2
⇒
W
=
6000

kg

⋅

m
2

s
−
2
∴
W
=
6000

J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000

7 0

3 years ago