Answer:
Uoe
Step-by-step explanation:
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Add the last two equations to eliminate <em>x</em> :
(<em>x</em> - 2<em>y</em> - 3<em>z</em>) + (- <em>x</em> + <em>y</em> + 2<em>z</em>) = 0 + 3
- <em>y</em> - <em>z</em> = 3
<em>y</em> + <em>z</em> = -3
Subtract this from the first equation to eliminate <em>z</em>, then solve for <em>y</em> :
(2<em>y</em> + <em>z</em>) - (<em>y</em> + <em>z</em>) = -8 - (-3)
<em>y</em> = -5
Plug this into the first equation to solve for <em>z</em> :
2(-5) + <em>z</em> = -8
<em>z</em> = 2
Plug both of these into either the second or third equations to solve for <em>x</em> :
<em>x</em> - 2(-5) - 3(2) = 0
<em>x</em> = -4
Answer:
Step-by-step explanation:
Given, f ( x ) = - x - 3
Let's find the value of f ( - 4 )
We know that , 
⇒
Subtract 3 from 4
⇒
Hope I helped!
Best regards!!
Answer: B
I hope this helped you
If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
</span><span>
y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
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