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sweet [91]
3 years ago
5

Rectangle ABCD is dilated to create rectangle A'B'C'D' . The width of rectangle ABCD is 8 feet. The width of rectangle A'B'C'D'

is 6 feet. The area of rectangle ABCD is 96 square feet.
What is the area of rectangle A'B'C'D' ? I NEED HELP PLEASE!!
Mathematics
1 answer:
likoan [24]3 years ago
5 0

Answer:

54 square feet

Step-by-step explanation:

The width of the rectangle ABCD is 8 feet and the area of the same rectangle is 96 square feet.

Hence, the length of the rectangle is (96 ÷ 8) = 12 feet.

Now, if the rectangle ABCD is dilated to rectangle A'B'C'D', then the length and the width of the new rectangle will be changed in the same ratio.

So, \frac{AB}{A'B'} = \frac{BC}{B'C'}  {Where AB is the length and BC is the width}

⇒ \frac{12}{A'B'} = \frac{8}{6}

⇒ A'B' = 9 feet

Therefore, the area of the dilated rectangle A'B'C'D' will be A'B' × B'C' = 9 × 6 = 54 square feet. (Answer)

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Answer:

x = -7.22 or -7 2/9

Step-by-step explanation:

-73 = 4(3x - 2) - 3x

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-65 = 9x

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8 0
3 years ago
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A metalworker has a metal alloy that is 30?% copper and another alloy that is 55?% copper. How many kilograms of each alloy shou
Sati [7]

Answer:

18 kilograms of 30% copper alloy is mixed with 72 kilograms of 55% copper alloy to makes  90 kg of a 50% copper alloy .

Step-by-step explanation:

Let us assume that the kilogram of 30% copper used to make alloy be x .

Let us assume that the kilogram of 55% copper used to make alloy be y .

As given

A metalworker has a metal alloy that is 30% copper and another alloy that is 55% copper.

The metalworker combine to create 90 kg of a 50% copper alloy .

Equation becomes

x  + y = 90

30% is written in the decimal form .

= \frac{30}{100}

= 0.30

55% is written in the decimal form .

= \frac{55}{100}

= 0.55

50% is written in the decimal form .

= \frac{50}{100}

= 0.50

Equation becomes

Concentration of 30% copper alloy × Number of kilograms of 30% copper alloy used + Concentration of 55% copper alloy × Number of kilograms of 55% copper alloy used = Concentration of 50% copper alloy × Number of kilograms of 50% copper alloy .

0.30x + 0.55y = 0.50 × 90

Simplify the above equation

\frac{30x}{100} + \frac{55y}{100} = \frac{90\times 50}{100}

30x + 55y = 4500

Two equation becomes

x  + y = 90

30x + 55y = 4500

Multiply x  + y = 90 by 30 and subtracted form 30x + 55y = 4500 .

30x - 30x + 55y - 30y = 4500 - 2700

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y = \frac{1800}{25}

y = 72 kilograms

Putting the value of y in the equation .

x  + 72 = 90

x = 90 - 72

x = 18 kilograms

Therefore 18 kilograms of 30% copper alloy is mixed with 72 kilograms of 55% copper alloy to makes  90 kg of a 50% copper alloy .

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Please help!!<br> I don’t know what to do
ira [324]

Answer:

x = 14.4

Step-by-step explanation:

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Answer:

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garri49 [273]

Answer:

20 dividido por 5 é 4

Eu espero que isso ajude

20 divide by 5 is 4 hope this helps!!!

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