Rectangle ABCD is dilated to create rectangle A'B'C'D' . The width of rectangle ABCD is 8 feet. The width of rectangle A'B'C'D'
1 answer:
Answer:
54 square feet
Step-by-step explanation:
The width of the rectangle ABCD is 8 feet and the area of the same rectangle is 96 square feet.
Hence, the length of the rectangle is (96 ÷ 8) = 12 feet.
Now, if the rectangle ABCD is dilated to rectangle A'B'C'D', then the length and the width of the new rectangle will be changed in the same ratio.
So, {Where AB is the length and BC is the width}
⇒
⇒ A'B' = 9 feet
Therefore, the area of the dilated rectangle A'B'C'D' will be A'B' × B'C' = 9 × 6 = 54 square feet. (Answer)
You might be interested in
Answer:
The number that belongs in the green P' = ([?], [ ]) with P' = (7, -8) box is;
7
Step-by-step explanation:
The coordinate of the given point 'P' is P = (3, -5)
The preimage of (x, y) after the translation, = (x-coordinate + 4, y-coordinate - 3)
Therefore, the translation, = T₍₄, ₋₃₎
Therefore, we have;
Preimage P(3, -5) under the translation T₍₄, ₋₃₎ gives the image P' as follows
P(3, -5) P'(3 + 4, -5 - 3) = P'(7, -8)
Therefore, the number that belongs in the green box is the x-coordinate value of the point P'(7, -8) which is seven.
Answer:
all work is shown and pictured
