Answer:

Step-by-step explanation:

<u>Expand the terms and simplify</u>
That's

Subtract 150 from both sides of the equation

<u>Divide both sides by 0.75</u>

We have the final answer as
<h3>x = - 5417.33 </h3>
Hope this helps you
Answer:
The correct option is 1.
Step-by-step explanation:
It is given that the Brian, Kelsey, and Geoff each have a remote-controlled car. They simultaneously started their cars and drove them in a straight line away from a motion sensor.
It means they are travelling at a constant rate.
Slope formula:

From the given table it is clear that the of Brian's car from the sensor is 34 at 1 sec and 38 at 3 sec. The rate of change is

It means the Brian's car traveled at the rate of 2 cm per sec.
From the given table it is clear that the of Brian's car from the sensor is 27 at 1 sec and 31 at 3 sec. The rate of change is

It means the Kelsey's car traveled at the rate of 2 cm per sec.
From the given table it is clear that the of Brian's car from the sensor is 27 at 1 sec and 33 at 3 sec. The rate of change is

It means the Geoff's car traveled at the rate of 3 cm per sec.
Since Brian's and Geoff's car traveled at the same rate, therefore option 1 is correct.
Answer:
An interesting experiment is given. We need to address various questions based on our knowledge of calculus.
Step 2
Part (a)
Time taken for the radius to grow to 2 cm = t1 = r/0.5 = 2/0.5 = 4 hours
Time taken for the radius to become 0 = t2 and the same can be obtained by solving:
r = 2 - √t2 = 0
Hence, t2 = 22 = 4 hours
Hence, the time duration of the entire experiment (from the introduction of the bacteria until its disappearance) = t1 + t2 = 4 + 4 = 8 hours
Step 3
Part (b)
r(t) = 0.5t for 0 ≤ t ≤ 4
and
r(t) = 2 - √(t - 4) for t > 2
Step-by-step explanation:
Step-by-step explanation:
as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.
v(t) = 60×ln(t + 1)
V(t) = 60 × integral(ln(t + 1)) between 0 and 5.
integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C
V(t) = 60 × ((t + 1)ln(t + 1) - t + C)
the distance traveled between t = 0 and t = 5 is then
60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =
= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =
= 60×(5.750556815... + C) - 60×C =
= 60×5.750556815... = 345.0334089... ≈ 345 km
Answer:
thanks
Step-by-step explanation: