Answer:
This college library would hold approximately ![6*10^{5}/tex] books.Step-by-step explanation:Having books on both sides, and each book being 25 centimeters (there is 100 cm in a meter, so 25 cm=0.25 m) deep, shelves must be around 50 cm (or 0.5 m) wide.If corridors must be 1,5 m wide, every two linear meters (perpendicular to corridors and shelves) of floor space there is 1.5 m of corridors and 0.5 m of shelves and that sequence repeats itself, i.e. there is 75% (1.5 of every 2 meters) of space occupied by corridors and 25% (0.5 of every 2 meters) occupied by shelves, that is:[tex]Floor space_{shelves}=Total floor space*proportion of shelves=3500m^{2} *0.25=875m^{2}](https://tex.z-dn.net/?f=6%2A10%5E%7B5%7D%2Ftex%5D%20books.%3C%2Fp%3E%3Cp%3EStep-by-step%20explanation%3A%3C%2Fp%3E%3Cp%3EHaving%20books%20on%20both%20sides%2C%20and%20each%20book%20being%2025%20centimeters%20%28there%20is%20100%20cm%20in%20a%20meter%2C%20so%2025%20cm%3D0.25%20m%29%20deep%2C%20shelves%20must%20be%20around%2050%20cm%20%28or%200.5%20m%29%20wide.%3C%2Fp%3E%3Cp%3EIf%20corridors%20must%20be%201%2C5%20m%20wide%2C%20every%20two%20linear%20meters%20%28perpendicular%20to%20corridors%20and%20shelves%29%20of%20floor%20space%20there%20is%201.5%20m%20of%20corridors%20and%200.5%20m%20of%20shelves%20and%20that%20sequence%20repeats%20itself%2C%20i.e.%20there%20is%2075%25%20%281.5%20of%20every%202%20meters%29%20of%20space%20occupied%20by%20corridors%20and%2025%25%20%280.5%20of%20every%202%20meters%29%20occupied%20by%20shelves%2C%20that%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DFloor%20space_%7Bshelves%7D%3DTotal%20floor%20space%2Aproportion%20of%20shelves%3D3500m%5E%7B2%7D%20%2A0.25%3D875m%5E%7B2%7D)
Knowing that every square meter of floor space occupied by shelves is in reality eight (because of being 8 shelves high) square meters of shelve space where to put books and that the average area of a book is
![Area occupied=depth*width=0.25m*0.05m=0,0125m^{2} per book](https://tex.z-dn.net/?f=Area%20occupied%3Ddepth%2Awidth%3D0.25m%2A0.05m%3D0%2C0125m%5E%7B2%7D%20per%20book)
Having all the necessary data, we estimate how many books would this college library hold:
![Books=\frac{Shelve space}{area_{book} } =\frac{875m^{2}*8 }{0.0125\frac{m^{2} }{book} } =560000 books](https://tex.z-dn.net/?f=Books%3D%5Cfrac%7BShelve%20space%7D%7Barea_%7Bbook%7D%20%7D%20%3D%5Cfrac%7B875m%5E%7B2%7D%2A8%20%7D%7B0.0125%5Cfrac%7Bm%5E%7B2%7D%20%7D%7Bbook%7D%20%7D%20%3D560000%20books)
As it is an estimate, we round it up to the nearest hundred-thousand, i.e., approximately [tex]6*10^{5}/tex] books can be shelved on this library
Answer:
um i am also lokking for the same thing
The ramp is simply a right triangle when viewed from the side. The rise is the height of the triangle and the run is the length or base. The slope of the ramp is the angle that the ramp makes with the ground. Plug those values into the formula for tanФ = opposite/adjacent or rise/run and solve for Ф. You should end up with 0.23
Answer:
The Associative Property of Addition
Step-by-step explanation:
illustrated by the statement (3+2.8) + 5= 3+(2.8 +5). So D
Given:
For a function f,
.
To find:
The coordinates of a point on the graph of f.
Solution:
We have,
![10 = f(-4)](https://tex.z-dn.net/?f=10%20%3D%20f%28-4%29)
It means the value of function f is 10 at -4.
On a coordinate plane x-axis represents the input values and y-axis represents the output values of a function. So,
x-coordinate = input value = -4
y-coordinate = output value = 10
Therefore, the required coordinates of a point on the graph of f are (-4,10).